Answer:
Margin of Error=M.E= ± 0.0113
Explanation:
Margin of Error= M.E= ?
Probability that watched network news programs = p = 0.4
α= 95%
Margin of Error =M.E= zₐ/₂√p(1-p)/n
Margin of Error=M.E= ±1.96 √0.4(1-0.4)/7200
Margin of Error=M. E = ±1.96√0.24/7200
Margin of Error=M. E- ±1.96* 0.005773
Margin of Error=M.E= ±0.0113
The Margin of Error is the estimate of how much error is possible as a result of random sampling.
def zipZapZop():
number = int(input("Enter the number: "))
dictionary = {3: "zip", 5: "zap", 7: "zop"}
amount = 0<em> #amount of non-divisible numbers by 3, 5 and 7</em>
<em> for key, value in dictionary.items():</em>
if(number%key == 0): <em>#key is the number</em>
print(value) <em>#value can be or zip, or zap, or zop</em>
else: amount += 1 #the number of "amount" increases every time, when the number is not divisible by 3, or 5, or 7
if(amount == 3): print(number) <em>#if the number is not by any of them, then we should print the number</em>
zipZapZop()
(1) Power supply (6) motherboard (11) Drive Bay
(2) hard drive (7) Central Processing Unit (CPU) (12) Floppy Drive
(3) expansion card (8) Random Access Memory (RAM) (13)Speaker
(4) expansion slot (9) CD-ROM (14) Video Connecter
(5) Read Only Memory (10)Power Cord Plug (15) Fan
B. training is the correct answer
Answer:
A: A ROM chip is non-volatile and will keep its data in the case of a power failure. A RAM chip is volatile and will wipe its data in the case of a power failure.
Explanation:
ROM chips were widely used at the time of the old consoles, because with it you had an extremely fast and non-volatile memory, but this technology is very expensive and started to use CDs in the Consoles, while the RAM memory is a memory of execution random (RAM = RANDOM ACESS MEMORY).
