d = 3 , a₁₂ = 40 and S = 7775
In an arithmetic sequence the nth term and sum to n terms are
<h3>• a
= a₁ + (n-1)d</h3><h3>• S
=
[2a + (n-1)d]</h3><h3>
where d is the common difference</h3><h3>a₆ = a₁ + 5d = 22 ⇒ 7 + 5d = 22 ⇒ 5d = 15 ⇔ d = 3</h3><h3>a₁₂ = 7 + 11d = 7 +( 11× 3) = 7 + 33 = 40</h3><h3>S₁₀₀ =
[(2×7) +(99×3)</h3><h3> = 25(14 + 297) = 25(311)= 7775</h3>
Answer:
15/4 please let me know if this helped you :)
Step-by-step explanation:
0.75*5=3.75 or 15/4
all of your answers are less than 3/4ths of a mile...she is increasing the amount she runs not decreasing.
Answer:
$380
Step-by-step explanation:
Amount invested in October 2001 = $500
If 2% is lost on stock each month, amount lost every month will be 2% of $500
= 2/100×$500
= $10
In order to know how much the stock will cost by October 2002, we need to know the number of month there is between October 2001 and October 2002.
The number of months within this period is 12months
If $10 is lost per month, the total stock lost for 12months will be
$10×12 = $120
Stock worth by October 2002 = Money invested - Total stock loss
Stock worth by October 2002 = $500-$120
= $380
Answer:
Only one <u>must</u> be true
Step-by-step explanation:
Answer:
If circumference = 25, then 90 degrees (one quarter of a circle) = 25 / 4 = 6.25 meters.
Step-by-step explanation: