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The equation that has the solution is 3x^2 - 10x + 6 = 0
The solution is given as:
The solution to a quadratic equation is
By comparing both equations, we have:
-b = 5
b^2 - 4ac = 7
2a = 3
Solve for b in -b = 5
b = -5
Solve for a in 2a = 3
a = 1.5
Substitute values for a and b in b^2 - 4ac = 7
(-5)^2 - 4 * 1.5c = 7
Evaluate
25 - 6c = 7
Subtract 25 from both sides
-6c = -18
Divide by - 6
c = 3
So, we have:
a = 1.5
b = -5
c = 3
A quadratic equation is represented as:
ax^2 + bx + c = 0
So, we have:
1.5x^2 - 5x +3 = 0
Multiply through by 2
3x^2 - 10x + 6 = 0
Hence, the equation that has the solution is 3x^2 - 10x + 6 = 0
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Answer:
angle CAB = 113.8 degree
angle ABC = 35.6 degree
angle BCA = 30.6 degree
Step-by-step explanation:
Given data:
A(1, 0, −1),
B(5, −3, 0),
C(1, 5, 2)
calculate the length of side by using the distance formula
so
AB = (5,-3,0) - (1,0,-1) = (4,-3,1)
AC= (1,5,2) - (1,0,-1) = (0,5,3)
|AB|
|AC| =
From following formula, calculate the angle between the two side i.e Ab and AC
AB.AC = |AB|*|AC| cos ∠CAB
(4,-3,1).(0,5,3)
4*0 -3*5 +1*3
-12 =
cos ∠CAB = - 0.404
angle CAB = 113.8 degree
BA =B- A = (1,0,-1) - (5,-3,0) = (-4,3,-1)
BC = (1,5,2)-(5,-3,0) = (-4,8,2)
|BA| = \sqrt{(26)}
|BC|
BA.BC = |BA|*|BC|* cosABC
(-4,3,-1).(-4,8,2) =
16+24-2
cos ∠ABC = 0.813
angle ABC = 35.6 degree
we know sum of three angle in a traingle is 180 degree hence
sum of all three angle = 180
angle BCA + 35.6 + 113.8 = 180
angle BCA = 30.6 degree