Answer:
The space inside the box = 2197 in³ - 1436.76 in³ is 760.245 in³.
Step-by-step explanation:
Here we have the volume of the cube box given by the following relation;
Volume of cube = Length. L × Breadth, B × Height, h
However, in a cube Length. L = Breadth, B = Height, h
Therefore, volume of cube = L×L×L = 13³ = 2197 in³
Volume of the basketball is given by the volume of a sphere as follows;
Volume = 
Where:
r = Radius = Diameter/2 = 14/2 = 7in
∴ Volume of the basketball = 
Therefore, the space inside the box that is not taken up by the basketball is found by subtracting the volume of the basketball from the volume of the cube box, thus;
The space inside the box = 2197 in³ - 1436.76 in³ = 760.245 in³.
19,700,000 because 19 million is 19,000,000 and 700,000 is 700,000 add thise together and you get 19,700,000
Answer:
Please see the answer below
Step-by-step explanation:
a. Since there’s no restrictions .Therefore , the number of ways = 7!*150 = 756000
b. The number of ways such that the 4 math books remain together
The pattern is as follows: MMMMEEE, EMMMMEE, EEMMMME, and EEEMMMM
Where M = Math’s Book and E= English Book.
Number of ways = 4!*8!*4*150= 86400 ways.
c. The number of ways such that math book is at the beginning of the shelf
The number of ways = 6!*4*150 = 432000
d. The number of ways such that math and English books alternate
The number of ways = 150*4!*3! =2160 ways
e. The number of ways such that math is at the beginning and an English book is in the middle of the shelf. The number of ways = 4*3*5!*150 =216000 ways.
D.) because there are 5 caterpillars in every tree (t) and then you have to add the 10 that are on the ground giving you the total amount of caterpillars (c)
Step-by-step explanation:
THE G.C.F IS 9W^2 AS ALL THE THREE MONOMIALS CAN ONLY BE DIVIDED BY IT..AFTER THAT IT WILL CHANGE IN DECIMAL/FRACTIONAL FORM.