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k0ka [10]
3 years ago
5

John has 6 pairs of pants and 3 shirts. How many possible outfits consisting of one shirt and

Mathematics
2 answers:
Agata [3.3K]3 years ago
5 0
I think it’s 18 :) so yeah
Step2247 [10]3 years ago
4 0

Answer:

18

Step-by-step explanation:

3 shirts for each pants

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I NEED HELP!!!!!!!!!!!!!!!!!!
ratelena [41]

Answer:

thats easy

Step-by-step explanation:

but thanks 4 the points

4 0
2 years ago
Tiffany is sending a package that may not exceed 16 pounds. the package contains books that weigh a total of 9 3/8 pounds. the o
babunello [35]
Yes Tiffany will be able to
5 0
2 years ago
How to prove this using trig identities?
Pavlova-9 [17]

Step-by-step explanation:

tanB + cotB = (sinB)/(cosB) + (cosB)/(sinB)

 

                      = (sin2B + cos2B)/[(cosB)(sinB)]

 

                       = 1/[(cosB)(sinB)]

 

                        = (1/cosB)(1/sinB)

 

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7 0
3 years ago
It is a well-known fact that 50% of the general population are rascals (P(R) = 0.5) and 50% of the general population are not ra
aleksley [76]

Answer:

The answer is D. 0.75

Step-by-step explanation:

Let call R the event that a person is rascal, RC a person is not rascal, TH a person use top hat and NTH a person don’t use top hat.  

From the information on the question we have 4 options with their respective probability:

1. A person could be rascal and use top Hat: this probability is calculate as the multiplication of the probability of be a rascal (0.5) and use a top hat (0.9), then:

P(R y TH)=0.5*0.9=0.45

2. A person could be rascal and don’t use top Hat: this probability is calculate as the multiplication of the probability of be a rascal (0.5) and not use a top hat (0.9), then:

P(R y NTH)=0.5*0.1=0.05

3. A person could be not rascal and use top Hat: this probability is calculate as the multiplication of the probability of not be a rascal (0.5) and use a top hat (0.3), then:

P(RC y TH)=0.5*0.3=0.15

4. A person could be not rascal and not use top Hat: this probability is calculate as the multiplication of the probability of not be a rascal (0.5) and not use a top hat (0.7), then:

P(RC y NTH)=0.5*0.7=0.35

Then the probability that a person is a rascal given that he is wearing a top hat could be written and calculate as:

P(R/TH)=\frac{P(R y TH)}{P(TH)}

For calculate P(TH) we need to sum all the option in which TH is involve so:

P(TH) = P(R y TH)+ P(RC y TH)

P(TH)=0.45+0.15=0.6

Replacing values on the first equation we get:

P(R/TH)=\frac{0.45}{0.6} =0.75

So, the probability that a person is a rascal given that he is wearing a top hat is 0.75

5 0
3 years ago
A water balloon has a diameter of 6 inches. How many cubic inches of water does it contain when it is 3/4 full
Travka [436]
Below are the choices that can be found from other sources:

A) 36 pi 
<span>B) 6 pi </span>
<span>C) 27 pi </span>
<span>D) 216 pi </span>
<span>E) 48 pi
</span>
A sphere's volume is (4/3)*pi*r^3. 
<span>The diameter of the balloon is 6 inches. The diameter is twice the radius. The radius is 3 inches. </span>

<span>(4/3)*pi*3^3 = 36 * pi </span>

<span>But the balloon is only 3/4 full. So </span>

<span>36 * (3/4) * pi = 27 * pi. </span>

<span>The balloon has 27 pi cubic inches of water.</span>
7 0
3 years ago
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