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k0ka [10]
3 years ago
5

John has 6 pairs of pants and 3 shirts. How many possible outfits consisting of one shirt and

Mathematics
2 answers:
Agata [3.3K]3 years ago
5 0
I think it’s 18 :) so yeah
Step2247 [10]3 years ago
4 0

Answer:

18

Step-by-step explanation:

3 shirts for each pants

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If ​f(x)equals 2xminus5 and ​k(x)equals ​f(xplus3​), write the equation for​ k(x).
ololo11 [35]
F(x)=2x-5
k(x)=f(x+3)=2(x+3)-5=2x+6-5=2x+1

k(x)=2x+1
7 0
3 years ago
BC =<br> Round your answer to the nearest hundredth.<br> ?<br> C<br> B<br> 50°<br> 7<br> А
umka21 [38]

Answer:

The answer is 8.34

U have to use the SOH CAH TOA method

In this case I used tan

so,

tan 50= BC/7

solve for BC= 7* tan 50= 8.34

6 0
3 years ago
How can you tell if an ordered pair (x,y) is a solution or a system of linear equations?
zubka84 [21]

Answer:

you will know because it you do the system of whatever thingy and there are no two dots in the same row and the line is straight in either a negative or positive slope at a diagonal the equation is linear and its a function.

Step-by-step explanation:

The image is an example of a linear equation that is both a function and positive lenear

8 0
3 years ago
Read 2 more answers
TEST quest helpppp 30pts
enyata [817]

Answer:

i think it is 1

Step-by-step explanation:

3 0
3 years ago
A guitar string is plucked at a distance of 0.6 centimeters above its resting position and then released, causing vibration. The
liubo4ka [24]

Answer:

The equation that represents the motion of the string is given by:

y =Ae^{-kt}\cos(2\pi ft)     .....[1] where t represents the time in second.

Given that: A = 0.6 cm (distance above its resting position) , k = 1.8(damping constant) and frequency(f) = 105 cycles per second.

Substitute the given values in [1] we get;

y =0.6e^{-1.8t}\cos(2\pi 105t)  

or

y =0.6e^{-1.8t}\cos(210\pi t)  

(a)

The trigonometric function that models the motion of the string is given by:

y =0.6e^{-1.8t}\cos(210\pi t)

(b)

Determine the amount of time t that it takes the string to be damped so that -0.24\leq y \leq0.24

Using graphing calculator for the equation

y =0.6e^{-1.8x}\cos(210\pi x)

let x = t (time in sec)  

Graph as shown below in the attachment:

we get:

the amount of time t that it takes the string to be damped so that -0.24\leq y \leq0.24 is, 0.5 sec


4 0
3 years ago
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