Question

What is the vertex of f(x) = 3(x+2)^2 -1

Answer 1

Answer:

$The~vertex~of~parabola~f(x) = a(x-h)^2+k~is~(h,k).\\Given~equation~of~parabola~is:\\f(x) = 3(x+2)^2-1\\So,~ h =-2 ~and~k=-1\\Therefore,~(-2,-1)~is~the~vertex~of~parabola.$