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2 years ago

12

HELP HELP HELP HELP FAST

2 answers:

Nonamiya [84]2 years ago

7 0

Answer:

[I didn't do it right]

Step-by-step explanation:

neonofarm [45]2 years ago

5 0

[Deleted since it has been said to be wrong and I would not like to spread misinformation]

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3 years ago

6. Are these triangles similar? If they are, name the postulate or theorem that proves they are.

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2 years ago

Write the equation of the line in fully simplified slope-intercept form.

Lina20 [59]

Answer:

$y=-6x+2$

Step-by-step explanation:

Hi there!

Slope-intercept form: $y=mx+b$ where <em>m</em> is the slope and <em>b</em> is the y-intercept (the value of y when x=0)

<u>1) Determine the slope (</u><u><em>m</em></u><u>)</u>

$m=\displaystyle \frac{y_2-y_1}{x_2-x_1}$ where two points that fall on the line are $(x_1,y_1)$ and $(x_2,y_2)$

Given the graph, we determine which points we could use. For example, we could use the two points $(0,2)$ and $(1,-4)$ :

$m=\displaystyle \frac{-4-2}{1-0}\\\\m=\displaystyle \frac{-6}{1}\\\\m=-6$

Therefore, the slope of the line is -6. Plug this into $y=mx+b$ :

$y=-6x+b$

<u>2) Determine the y-intercept (</u><u><em>b</em></u><u>)</u>

Recall that the y-intercept occurs when x=0. Given the point (0,2), we know that the y-intercept is 2. Plug this into $y=-6x+b$ :

$y=-6x+2$

I hope this helps!

5 0

2 years ago

a truck weighs 1 ton 1350 pounds the weighs limit for a bridge is given in pounds how many pounds does the truck weigh

topjm [15]

The answer is 3350 pounds

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2 years ago

Read 2 more answers

What is the vertex of the quadratic function f(x)=x2+6x+16? Write your answer

Olenka [21]

Answer:

The vertex of the quadratic function is:

$(x_{v}, y_{v})=\left(-3,\:7\right)$

Step-by-step explanation:

Given the function

$f\left(x\right)=x^2+6x+16$

As the vertex of the form $y=ax^2+bx+c$ is defined as:

$x_v=-\frac{b}{2a}$

As the quadratic function of parabola params are

$a=1,\:b=6,\:c=16$

so

$x_v=-\frac{b}{2a}$

$x_v=-\frac{6}{2\cdot \:1}$

$x_v=-3$

Putting $x_v=-3$ to determine $y_v$

$y_v=\left(-3\right)^2+6\left(-3\right)+16$

$y_v=3^2-18+16$

$y_v=9-2$

$y_v=7$

Therefore, the vertex of the quadratic function is:

$(x_{v}, y_{v})=\left(-3,\:7\right)$

5 0

3 years ago