2 consecutive even integers....x and x + 2
x + x + 2 = 66
2x + 2 = 66
2x = 66 - 2
2x = 64
x = 64/2
x = 32
x + 2 = 32 + 2 = 34
ur 2 integers are : 32 and 34
We have 7y = 4x + 14;
Then, y = (4/7)x + 2;
The slope of this line is 4/7;
Because another line is parallel with the first one, the chosen slope is 4/7.
Answer:
y = 66x + 340
Step-by-step explanation:
The question asks to give the slope-intercept equation of a line with the slope given and it passes through a given line.
Generally, the equation of a line is given by:
y = mx + c, where m is the slope and c is the intercept. We have the slope given but we do not have the intercept. Hence, the first thing we do is to find the value of the intercept. We calculate that as follows:
since the line passes through a point, we substitute the values of the ordinate and the abscissa in the general equation of the line.
This means; 10 = 66(-5) + C
C = 10 + 330 = 340
Hence, the general equation of the line is;
y = 66x + 340
Answer:
615.8in^3
Step-by-step explanation:
Given data
Radius= 14in
The expression for the area of circle is given as
A= πr^2
Area= 3.142*14^2
Area= 3.142*196
Area= 615.832in^3
Hence the area is 615.8in^3
I'm using PEDMAS.
Multiplication first.
2 • 4 = 8
Subtraction.
20 - 4 = 16
16 + 8 = 24
Please let me know if you spot any errors (especially the fraction operation)
