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ExtremeBDS [4]
2 years ago
15

Describe the graph of the quadratic from the original y = x^2 .

Mathematics
1 answer:
Citrus2011 [14]2 years ago
4 0

Answer:

a. Narrower

b. Shifts left

c. Opens up

d. Shifts up

Step-by-step explanation:

The original quadratic equation is y = x²

The given quadratic equation is y = 5·(x + 4)² + 7

The given quadratic equation is of the form, f(x) = a·(x - h)² + k

a. A quadratic equation is narrower than the standard form when the coefficient is larger than the coefficient in the original equation

The quadratic coefficient is 5 > 1 in the original, therefore, the quadratic equation is <em>narrower</em>

b. Given that the given quadratic equation has positive 'a', and 'b', and h = -4, therefore, the axis of symmetry <em>shifts left</em>

c. The quadratic coefficient is positive, (a = 5), therefore, the quadratic equation <em>opens down</em>

d. The value of 'k' gives the vertical shift, therefore, the given quadratic equation with k = 7, <em>shifts up.</em>

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mihalych1998 [28]

Answer:

f(x)=5(x-2)^{2}+6

Step-by-step explanation:

we have

f(x)=5x^{2} -20x+26

This is the equation of a vertical parabola open upward

The vertex is a minimum

The equation of a vertical parabola in vertex form is equal to

f(x)=a(x-h)^2+k

where

(h,k) is the vertex

Convert the given function to vertex form

Factor the leading coefficient

f(x)=5(x^{2} -4x)+26

Complete the square

f(x)=5(x^{2} -4x+4)+26-20

f(x)=5(x^{2} -4x+4)+6

Rewrite as perfect squares

f(x)=5(x-2)^{2}+6 ------> equation in vertex form

The vertex is the point (2,6)

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Which graph represents the function f(x) = (x – 3)2?
hjlf

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7 0
2 years ago
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You start driving north for 24 miles, turn right, and drive east for another 10 miles. At the end of driving, what is your strai
yawa3891 [41]

Answer:

26 miles

Step-by-step explanation:

Given: 24 miles drive to north.

          10 miles drive to east.

Driving pattern form a right angle triangle, which has three leg including straight line distance from starting point (hypotenous).

Now, using Pythogorean theoram to find straight line distance from starting point.

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Where, h is hypotenous

            a is opposite leg

            b is adjacent leg.

⇒h²= 24^{2} + 10^{2}

⇒h^{2} = 576+100

⇒h^{2} = 676

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⇒h=\sqrt{676}

∴ h= \pm 26

Ignoring -26 as distance cannot be negative.

Hence, 26 miles is the straight line distance from starting point.

8 0
3 years ago
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