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2 years ago

Describe the graph of the quadratic from the original y = x^2 .

Mathematics

1 answer:

Citrus2011 [14]2 years ago

4 0

Answer:

a. Narrower

b. Shifts left

c. Opens up

d. Shifts up

Step-by-step explanation:

The original quadratic equation is y = x²

The given quadratic equation is y = 5·(x + 4)² + 7

The given quadratic equation is of the form, f(x) = a·(x - h)² + k

a. A quadratic equation is narrower than the standard form when the coefficient is larger than the coefficient in the original equation

The quadratic coefficient is 5 > 1 in the original, therefore, the quadratic equation is narrower

b. Given that the given quadratic equation has positive 'a', and 'b', and h = -4, therefore, the axis of symmetry shifts left

c. The quadratic coefficient is positive, (a = 5), therefore, the quadratic equation opens down

d. The value of 'k' gives the vertical shift, therefore, the given quadratic equation with k = 7, shifts up.

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3 years ago

What is the slope of the line?

Talja [164]

Answer:

$\displaystyle m=1$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Slope Formula: $\displaystyle m=\frac{y_2-y_1}{x_2-x_1}$

Step-by-step explanation:

Step 1: Define

Find points from graph.

Point (-1, 0)

Point (0, 1)

Step 2: Find slope m

Simply plug in the 2 coordinates into the slope formula to find slope m

Substitute in points [SF]: $\displaystyle m=\frac{1-0}{0--1}$
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[Fraction] Subtract/Add: $\displaystyle m=\frac{1}{1}$
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7 0

2 years ago

Find the zeroes of polynomial x² -(√3+1)x+√3

r-ruslan [8.4K]

X² - √3x -x +√3

x(x-√3) -(x-√3)

(x-√3)(x-1)

zeroes are x-√3 = 0
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and x-1 =0
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3 years ago

A simple random sample of size nequals10 is obtained from a population with muequals68 and sigmaequals15. (a) What must be true

valentina_108 [34]

Answer:

(a) The distribution of the sample mean ( $\bar x$ ) is N (68, 4.74²).

(b) The value of $P(\bar X$ is 0.7642.

Step-by-step explanation:

A random sample of size n = 10 is selected from a population.

Let the population be made up of the random variable X.

The mean and standard deviation of X are:

$\mu=68\\\sigma=15$

(a)

According to the Central Limit Theorem if we have a population with mean μ and standard deviation σ and we take appropriately huge random samples (n ≥ 30) from the population with replacement, then the distribution of the sample mean will be approximately normally distributed.

Since the sample selected is not large, i.e. n = 10 < 30, for the distribution of the sample mean will be approximately normally distributed, the population from which the sample is selected must be normally distributed.

Then, the mean of the distribution of the sample mean is given by,

$\mu_{\bar x}=\mu=68$