Answer:
It's below in the explanation
Explanation
1. x has to be greater than 2. So 3 and 4 both work 
2. x has to be less than 22. So 21 and 20 both work 
3. t has to be less than 5. So 3 and 4 both work 
4. There isn't a number there. what is 5 less that? 
5. j has to be less than 5 so 5 and 4 both work
6. y has to be less than 4. So 4 and 3 both work
7. B has to be greater than 26. so 26 27 and 28 all work 
8.There isn't a number there
9.b can be 3 or greater than 3. 
10.z can be 6 or greater than 6
Hope this Helps!
 
        
             
        
        
        
Answer:
<h2>For c = 5 → two solutions</h2><h2>For c = -10 → no solutions</h2>
Step-by-step explanation:
We know

for any real value of <em>a</em>.
|a| = b > 0 -  <em>two solutions: </em>a = b or a = -b
|a| = 0 - <em>one solution: a = 0</em>
|a| = b < 0 - <em>no solution</em>
<em />
|x + 6| - 4 = c
for c = 5:
|x + 6| - 4 = 5           <em>add 4 to both sides</em>
|x + 6| = 9 > 0   <em>TWO SOLUTIONS</em>
for c = -10
|x + 6| - 4 = -10           <em>add 4 to both sides</em>
|x + 6| = -6 < 0   <em>NO SOLUTIONS</em>
<em></em>
Calculate the solutions for c = 5:
|x + 6| = 9 ⇔ x + 6 = 9 or x + 6 = -9         <em>subtract 6 from both sides</em>
x = 3 or x = -15
 
        
             
        
        
        
just realized this is an old question