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stepladder [879]
3 years ago
10

Help meeeeeeeeeeeeeee pls

Mathematics
1 answer:
WITCHER [35]3 years ago
5 0

Answer:

Area = 15.36 ft

Step-by-step explanation:

First find the area of the dotted line triangle using the formula: base x height x 1/2, which would be 1.2ft x 12.8 x 1/2 = 7.68ft.

Next, add another triangle at the top, mirroring the shown triangle, of the parallelogram.

Then, find the area of the shape as though it were a rectangle. (base x height) - 2.4 x 12.8 = 30.72.

Next, multiply the area of the invisible triangle by 2, 7.68 x 2 = 15.36ft

and Finally, subtract the area of the rectangle shape of the the sum of the two invisible triangles, 30.72 - 15.36 = 15.36ft

The area of the parallelogram is 15.36 ft.

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What is the expressions that equal 372,000
sveta [45]

Answer:

Look below

Step-by-step explanation:

372,000 = 372,000

372,000 = 300,000 + 70,000 + 2,000

Hopefully this helps you

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4 0
3 years ago
Find the value of each variable<br> x = <br> y=
Karolina [17]

Answer:

x=9

y=9\sqrt{2}

Step-by-step explanation:

This is a special type of triangle known as a 45-45-90 triangle.

The ratio for the sides of this triangle are x:x:x\sqrt{2}

Meaning that the two sides other than the hypotenuse are equal, so in this triangle x=9 because it is not a hypotenuse.

The hypotenuse, however, is the value of one side multiplied by \sqrt{2}.

In this case it is 9, so 9*\sqrt{2} = 9\sqrt{2}

7 0
2 years ago
Please help!! x = 2 - 3 cos t, y = 1 + 4 sin t in rectangular form?<br><br> thank you! :)
sukhopar [10]

Answer:

\frac{(x-2)^2}{9}+\frac{(y-1)^2}{16}=1

Step-by-step explanation:

x=2-3\cos(t)

y=1+4\sin(t)

Let's solve for \cos(t) in the first equation and then solve for \sin(t) in the second equation.

I will then use the following identity to get right of the parameter, t:

\cos^2(t)+\sin^2(t)=1 (Pythagorean Identity).

Let's begin with x=2-3\cos(t).

Subtract 2 on both sides:

x-2=-3\cos(t)

Divide both sides by -3:

\frac{x-2}{-3}=\cos(t)

Now time for the second equation, y=1+4\sin(t).

Subtract 1 on both sides:

y-1=4\sin(t)

Divide both sides by 4:

\frac{y-1}{4}=\sin(t)

Now let's plug it into our Pythagorean Identity:

\cos^2(t)+\sin^2(t)=1

\frac{x-2}{-3})^2+(\frac{y-1}{4})^2=1

\frac{(x-2)^2}{(-3)^2}+\frac{(y-1)^2}{4^2}=1

\frac{(x-2)^2}{9}+\frac{(y-1)^2}{16}=1

5 0
3 years ago
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It should be B

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3 years ago
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