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pochemuha
2 years ago
8

A student's pay of $23 an hour at a new job is $6 more than twice the amount the student earned per hour at an internship. Write

and solve an equation to find the hourly pay of the internship.
Mathematics
2 answers:
babunello [35]2 years ago
6 0
The equation would be 309.8=9.65x, where x=number of hours you worked this week. You would then solve the equation by dividing 309.8 by 9.65.
FinnZ [79.3K]2 years ago
6 0
Hey there!

To solve this problem, you'll first need to analyze what happens to the hourly wage of the internship, which can be represented by x, to get to the hourly wage of the student's new job, which is $23.00. The problem says that $23.00 is twice the amount of x, or 2x, plus $6.00, or + 6. 

Your equation will be 23 = 2x + 6. Now, you have to solve it. 

To solve an equation, you will need to combine your terms. This is easier to show than explain:

23 = 2x + 6

You can start out by subtracting 6 from +6, which will cancel out that term on the right side. Anything you do to one side is something you must repeat on the other, so subtract 6 from 23 on the left side, as well. 

23 = 2x + 6
– 6        – 6

17 = 2x

Now, you will cancel out the 2 in 2x by dividing that term by 2. Then, you'll repeat this on the left side to find what x is equal to. 

(17) ÷ 2 = (2x) ÷ 2

8.5 = x

The hourly wage of the intern job was $8.50. You can check this by plugging this number into your original equation and solving the equation. If it is equal to 23, the answer is correct. 

y = 2x + 6
y = 2(8.5) + 6
y = 17 + 6
y = 23

$8.50 is your final answer. 

Hope this helped you out! :-)
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Complete Question

The complete question is shown on the first uploaded image

Answer:

the null hypothesis is  H_o  :  \mu =  122

the alternative hypothesis is H_a  :  \mu \ne  122

The test statistics is  t =  - 1.761

The p-value is  p =  P(Z  <  t ) = 0.039119

so

    p  \ge 0.01

Step-by-step explanation:

From the question we are told that

   The population mean is  \mu  = 122

     The sample size is  n=  38

    The sample mean is  \= x  =  116 \ feet

     The standard deviation is \sigma  =  21

     

Generally the null hypothesis is  H_o  :  \mu =  122

                the alternative hypothesis is H_a  :  \mu \ne  122

Generally the test statistics is mathematically evaluated as

         t =  \frac { \= x - \mu }{\frac{ \sigma }{ \sqrt{n} } }

substituting values

         t =  \frac { 116 -  122 }{\frac{ 21 }{ \sqrt{ 38} } }

         t =  - 1.761

The p-value is mathematically represented as

      p =  P(Z  <  t )

From the z- table  

     p =  P(Z  <  t ) = 0.039119

So  

     p  \ge 0.01

 

         

     

           

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