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vazorg [7]
3 years ago
12

Find the value of X express each answer as a decimal rounded to the nearest tenth.

Mathematics
1 answer:
VMariaS [17]3 years ago
3 0

Answer:

x = 15.6

Step-by-step explanation:

use the pythagorean theorem:

a² + b² = c²

a = 9

b = x

c = 18

(9)² + x² = (18)²

81 + x² = 324                    subtract 81 from both sides

x² = 243                            take the square root of both sides

x = √243

x = 15.6

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Set up the equation to find the AREA of the SMALL rectangle with a length of (x) and width (x+7)
Igoryamba

<u>Answer:</u>

<h3>( x ) x ( x + 7 ) </h3>

<u>Step-by-step explanation:</u>

To find the area of a rectangle, we have to multiply the length with the width.

In the question, the given length is 'x' and the width given is 'x +7'

So, the area would be

( x ) x ( x + 7 )

The area = x^{2} + 7x

So, the equation to find the area of such a rectangle would be:-

( x ) x ( x + 7 )

7 0
3 years ago
<img src="https://tex.z-dn.net/?f=5x%20%2B%209%20%20%3D%203x%20%2B%201" id="TexFormula1" title="5x + 9 = 3x + 1" alt="5x + 9 =
marissa [1.9K]

Answer:

x = -4

Step-by-step explanation:

Take out 3x from both sides:

5x - 3x    =    3x - 3x

2x           =   0

2x + 9 = 1

Take out 9 from both sides:

9 - 9             =       1 - 9

0                  =      -8

Divide 2 from both sides:

\frac{2x}{2} = \frac{-8}{2}

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6 0
3 years ago
Read 2 more answers
45 POINTS At a high school football game, 4 out of every 7 students in line to buy a ticket wore a hat. If 350 students bought a
nataly862011 [7]

Step-by-step explanation:

Number of students who wore a hat

= 4/7 * Number of students who bought a ticket

= 4/7 * 350 students

= 200 students.

Number of students not wearing a hat

= Number of students who bought a ticket - Number of students who wore a hat

= 350 students - 200 students

= 150 students.

6 0
3 years ago
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Tanya [424]

Answer:

4

Step-by-step explanation:

6 0
3 years ago
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Given the below sequence:-1, -3, -5, -7, . . .
vekshin1

Answer:

A. The next 3 terms are —9, —11, —13

B. The sequence is Arithmetic

C. The sequence has a common difference of —2

Common difference = T2 — T1 or = T3 — T2

=T2 — T1 = —3 —(—1) = —2 or

= T3 — T2 = —5 —(—3) = —2

D. Tn = a + d(n—1)

a = first term = —1

d = Common difference = —2

n = 27

T27 = —1 + —2(27—1)

T27 = —1 + —2(26)

T27 = —1 —52

T27 = —53

3 0
3 years ago
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