Estimate: 19 + 17.77 = 37 B 31 35 D 41

601.584 to the nearest tenth

son4ous [18]

The answer is 601.6
:)))

7 0

2 years ago

Serena wants to solve the following system of equations in the most efficient way.

Marianna [84]

Answer:

Serina should have solved for x in the second equation because it has a coefficient of 1.

Step-by-step explanation:

we have

$2x+3y=18$ ----> equation A

$x+7y=31$ ---> equation B

we know that

To solve the system of equations in the most efficient way, solve for x equation B and then substitute the value of x in equation A

so

$x=31-7y$ ----> equation C

substitute equation C in equation A

$2(31-7y)+3y=18$

solve for y

$62-14y+3y=18\\11y=62-18\\11y=44\\y=4$

Find the value of x

substitute the value of y in the equation C

$x=31-7(4)=3$

The solution is (3,4)

therefore

Serina should have solved for x in the second equation because it has a coefficient of 1.

3 0

3 years ago

Read 2 more answers

Do u know what a rotio table or a in and out box if u do that how I have to solve it and I need to know the rule

SOVA2 [1]

Okay so an in and out box is a box is basically a tale. Do you have a rule ? so if you have a rule..(which i do not know) lets say the rule is +2. lets also say that the IN says 4. Then what would be the out ? The out would be whatever 4+2 is. So basically the "out" is the outcome.

6 0

2 years ago

Identify any transformations (translations, reflections, rotations) that are used in each corporate logo below. Some logos may h

lord [1]

Answer:

Check below

Step-by-step explanation:

There are rigid transformations that produce congruent figures: translation, rotation, and one transformation that produces a similar figure, namely: Dilation.

1) Toyota: translation, and Dilation.

Two ellipses translated within a larger ellipse.

2) 2 Reflections, or 4 rotations of the pre-image

We have two ways of drawing this figure. Either by reflection of the right and the lower one or by rotation.

3) CBS: Dilation of the circumference, inside a rhombus.

4) Mitsubishi: Reflection about the y axis, Rotation for the figure up.

e) Reflection

f) Translation

6 0

2 years ago

A single 6-sided die is rolled twice. The set of 36 equally likely outcomes is {(1,1), (1,2), (1,3), (1,4), left parenthesis

Dennis_Churaev [7]

Answer:

The probability of getting two numbers whose sum is greater than 9 and less than 13 is $\frac{1}{6}$

Step-by-step explanation:

Given : A single 6-sided die is rolled twice.

To find : The probability of getting two numbers whose sum is greater than 9 and less than 13 ?

Solution :

The set of 36 equally likely outcomes,

1 2 3 4 5 6

1 (1, 1) (1, 2) (1, 3) (1, 4) (1, 5) (1, 6)

2 (2, 1) (2, 2) (2, 3) (2, 4) (2, 5) (2, 6)

3 (3, 1) (3, 2) (3, 3) (3, 4) (3, 5) (3, 6)

4 (4, 1) (4, 2) (4, 3) (4, 4) (4, 5) (4, 6)

5 (5, 1) (5, 2) (5, 3) (5, 4) (5, 5) (5, 6)

6 (6, 1) (6, 2) (6, 3) (6, 4) (6, 5) (6, 6)

Getting two numbers whose sum is greater than 9 and less than 13

The favorable outcome is (4,6),(5,5),(5,6),(6, 4),(6, 5),(6, 6) = 6

The probability is given by,

$\text{Probability}=\frac{\text{Favorable Outcome}}{\text{Total Outcome}}$

$\text{Probability}=\frac{6}{36}$

$\text{Probability}=\frac{1}{6}$

Therefore, The probability of getting two numbers whose sum is greater than 9 and less than 13 is $\frac{1}{6}$

5 0

3 years ago