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3 years ago

-3r + 8 + 2r = -1. What is the value of r?

Mathematics

2 answers:

SashulF [63]3 years ago

8 0

-3r+8+2r=-1

-3r+2r=-1-8

-3r=-9r=9

barxatty [35]3 years ago

8 0

Answer:

r=9

Step-by-step explanation:

-3r+8+2r=-1

-3r+2r+8=-1

-r+8=-1

-r+8-8=-1-1

-r=-9

-r/-1=-9/-1

r=9

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3 years ago

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2 years ago

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notsponge [240]

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Step-by-step explanation:

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#Solve simultaneously to solve for x and y:

$(-3)^2=x^2+y^2\ \ \ \ \ \ \ \ \ \ i\\\\tan(-0\texdegree)=y/x\ \ \ \ \ \ \ \ ...ii\\\\y=x\ tan(-60\textdegree)\ \ \ \ \ \ \ ...iii\\\\\#substitute\ y \ in\ i\\\\(-3)^2=x^2+(x \ tan (-60\textdegree))^2\\\\9=x^2+3x^2\\\\x=\sqrt{9/4}=1.5\\\\y=1.5\ tan(-60\textdegree)=-2.5981\approx-2.6$

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3 years ago