All categories

2 years ago

Heeeeeeeeeeeeeeeeeeeeeelp

Mathematics

1 answer:

joja [24]2 years ago

3 0

You plug it in so it’ll be 11; 8; 5; 2

You might be interested in

How to measure a basketball court

Anna [14]

Well, by using a yard stick. Using a ruler is too small, for a basketball court, because it measures both feet and inches, and since a court is WAY BIGGER than that, then you have to use a yard stick to measure it.

8 0

3 years ago

In a class with 28 students, there are 19 boys. What is the ratio of girls to boys? 9:19 19:28 19:9 28:9

leva [86]

Answer:

9:19

Step-by-step explanation:

Total number of students = 28

Number of boys = 19

Number of girls = Total number of students - Number of boys = 28-19 = 9

Therefore, ratio of girls to boys = Number of girls/Number of boys = 9/19 = 9:19

5 0

3 years ago

Read 2 more answers

Four students grafted one linear function each

Brut [27]

Step-by-step explanation:

The answer is attached in this photo

8 0

3 years ago

Find the distance between points A(5, 4) and B(2, 0)

Debora [2.8K]

Answer:

The distance between point A and point B is 5 units

3 0

3 years ago

There are 210210210 students in a twelfth grade high school class. 909090 of these students have at least one sister and 1051051

BlackZzzverrR [31]

Answer:

(1) The value of P (A) is 0.4286.

(2) The value of P (B) is 0.50.

(3) The value of P (A ∩ B) is 0.2143.

(4) The the value of P (B|A) is 0.50.

(5) The events A and B are independent.

Step-by-step explanation:

The events are defined as follows:

A = a student in the class has a sister

B = a student has a brother

The information provided is:

N = 210

n (A) = 90

n (B) = 105

n (A ∩ B) = 45

The probability of an event E is the ratio of the favorable number of outcomes to the total number of outcomes.

$P(E)=\frac{n(E)}{N}$

The conditional probability of an event X provided that another event Y has already occurred is:

$P(X|Y)=\frac{P(A\cap Y)}{P(Y)}$

If the events X and Y are independent then,

$P(X|Y)=P(X)$

(1)

Compute the probability of event A as follows:

$P(A)=\frac{n(A)}{N}\\\\=\frac{90}{210}\\\\=0.4286$

The value of P (A) is 0.4286.

(2)

Compute the probability of event B as follows:

$P(B)=\frac{n(B)}{N}\\\\=\frac{105}{210}\\\\=0.50$

The value of P (B) is 0.50.

(3)

Compute the probability of event A and B as follows:

$P(A\cap B)=\frac{n(A\cap B)}{N}\\\\=\frac{45}{210}\\\\=0.2143$

The value of P (A ∩ B) is 0.2143.

(4)

Compute the probability of B given A as follows:

$P(B|A)=\frac{P(A\cap B)}{P(A)}\\\\=\frac{0.2143}{0.4286}\\\\=0.50$

The the value of P (B|A) is 0.50.

(5)

The value of P (B|A) = 0.50 = P (B).

Thus, the events A and B are independent.

6 0

3 years ago