Answer:
The area of an octagon whose perimeter is 120 cm is 1086.4 
Step-by-step explanation:
An octagon is a polygon with eight sides. If the lengths of all the sides and the measurement of all the angles are equal, the octagon is called a regular octagon.
There is a predefined set of formulas for the calculation of perimeter, and area of a regular octagon.
The perimeter of an Octagon is given by
and the area of an Octagon is given by
We know that the perimeter is 120 cm, solving for side length (a) in the perimeter formula we get
Now, we calculate the area
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Answer:
(x +1)^2 +(y +0.5)^2 = 22.25
Step-by-step explanation:
The center of the circle is the midpoint of the diameter, so is ...
(h, k) = ((-5, -3) +(3, 2))/2 = (-5+3, -3+2)/2 = (-1, -1/2)
The circle formula is then ...
(x -h)^2 +(y -k)^2 = r^2
(x -(-1))^2 +(y -(-1/2))^2 = r^2
We can find r^2 by substituting one of the points for (x, y).
(3 +1)^2 +(2 +1/2)^2 = r^2 = 16 +6.25 = 22.25
Then the circle equation is ...
(x +1)^2 +(y +0.5)^2 = 22.25
Answer:
13
Step-by-step explanation:
a pair=2
so 25/each pair of towns
25/2=12+1=13
2p+6a=$14
3p+9a=$21
3p+9a=21
Subtract 9a
3p=21-9a
divide all by 3
p=7-3a
plug it into start equations
2p+6a=14
2(7-3a)+6a=14
14-6a....+6a=14
this zeroes out...
