If the 13th term in a linear sequence is 92 and the 28th term in the sequence is
1 answer:
Answer:
64
Step-by-step explanation:
As the sequence is linear the rate of increase stays constant as we can see from the formula: so it increases by m every term. In this all we do is subtract 13 from 28 to find the number of terms in between:
28-13=15
now we find the difference between 152 and 92
152-92=60
now we divide 60 and 15
60÷15=4
So M is 4 meaning every term has a difference of 4.
So now we can subtract 6 from 13:
13-6=7
Then multiply the difference per term (4) by 7
4×7=28
Finally we subtract 28 from 92 (13th terms value)
92-28=64
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Answer:
X Intercepts: (2, 0), (-6, 0),
Y Intercepts: (0, – 12)
minimum: (-2,-16)
Step-by-step explanation:
A) what are the x intercepts
X- axis interception points of x²+ 4x– 12:
(2,0), (-6,0)
B)what is the y intercepts
Y-axis interception point of x² + 4X – 12:
(0, – 12)
X Intercepts: (2, 0), (-6, 0), Y Intercepts: (0, – 12)
C)what is the maximum and minimum value
Parabola equation in polynomial form
The parabola params are:
a=1, b=4,c= -12
xv= -b/2a
xv= -4/2.1
simplify
xv=-2
Plug in xv = -2 to find the yv value
yv= -16
Therefore the parabola vertex is (-2, – 16)
If a<0. then the vertex is a maximum value
If a>0. then the vertex is a minimum value
a=1
minimum=(-2,-16)
