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2 years ago

given sin theta=3/5 and 180°<theta<270°, find the following: a. cos(2theta) b. sin(2theta) c. tan(2theta)

Mathematics

1 answer:

Dennis_Churaev [7]2 years ago

8 0

I hope this will help uh.....

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We have a trapezoid and a triangle

area of trapezoid=(base1+base2) times 1/2height
area of traingle=1/2 base times height

triangle
base=18
height=12
area=1/2 times 12 times 18=108

trapezoid
to find height we do
17=12+height
subtrac 12
5=height

so
base1=14
base2=18
height=5
area=(14+18) times 1/2 times 5
area=32 times 1/2 times 5
area=80

total area=area of trapezoid+area of triangle
total area=80+108
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2 years ago

Read 2 more answers

If you order these 3 from Least I will give 20 points and mark as brilliant 1.)6 3/5, 7 3/4,6.55,6,7.09 2.) 3 8/20,-3.3,3.41,3.2

natulia [17]

Answer:

1.) 6, 6.55, 6 3/5, 7.09, 7 3/4

2.) -3.3, -3 3/12, 3.27, 3 8/20, 3.41

3.) -0.4, 1/25, 4/50, 12/100, 0.8

Explanation:

1.) 6 3/5, 7 3/4, 6.55, 6, 7.09

6 3/5 -> 6.6

7 3/4 -> 7. 75

Therefore: 6, 6.55, 6 3/5, 7.09, 7 3/4

2.) 3 8/20, -3.3, 3.41, 3.27, -3 3/12

3 8/20 -> 3.04

-3 3/12 -> -3.25

Therefore: -3.3, -3 3/12, 3.27, 3 8/20, 3.41

3.) 4/50, 0.8, 12/100, -0.4, 1/25

4/50 -> 0.08

12/100 -> 0.12

1/25 -> 0.04

Therefore: -0.4, 1/25, 4/50, 12/100, 0.8

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2 years ago

given sin theta=3/5 and 180°<theta<270°, find the following: a. cos(2theta) b. sin(2theta) c. tan(2theta)​

given sin theta=3/5 and 180°<theta<270°, find the following: a. cos(2theta) b. sin(2theta) c. tan(2theta)