Answer:
For question 3, you would just add 2 to the x values and subtract 2 from the y values, so it would be:
J' (-2, 5)
K' (2, 6)
L' (1, 2)
M' (-3, 1)
For question 4 you would subtract 7 from the x values and 6 from the y values, and that would be:
W' (-6, 1)
X' (-1, -1)
Y' (-3, -6)
Z' (-8, -4)
For question 9 you would end up with:
X' (6, -5)
Y' (7, 1)
Z' (4, 0)
For question 10 you would end up with:
Q' (-1, 2)
R' (1, 7)
S' (-2, 6)
T' (-4, 1)
For question 11 you would end up with:
L' (4, 1)
M' (8, 5)
N' (6, 7)
P' (2, 3)
For question 12 you would end up with:
G' (6, -7)
H' (6, -4)
I' (1, -7)
Hope this is what you were looking for!
Step-by-step explanation:
Assuming this is a 6-sided die:
(a) 1/6 = 0.167 or 16.7 %
(b) zero (numbers on the die are 1-6)
(c) 3/6 = 50% (can be 2, 4, or 6)
(d) 3/6 = 50% (of the numbers you could roll, 2, 3, and 5 are prime)
7and 2 3rds divided by 5 and 3 8ths is more then one
Answer:
-5 - 3x > 10
Step-by-step explanation:
x = -6
Plug in the x value for each inequality:
-5 - 3(-6) > 10
-5 + 18 > 10
13 > 10
True
-3 - 5(-6) < -14
-3 + 30 < -14
27 < -14
False
1 - 2(-6) > 13
1 + 12 > 13
13 > 13
False
2 - (-6) < -3
2 + 6 < -3
8 < -3
False
Only one of these is true; that is the answer.
The quotient of the fraction n³ / (2n - 6) ÷ n³ / (3n - 9) is 2/3
<h3 /><h3>How to solve fraction</h3><h3 />
n³ / (2n - 6) ÷ n³ / (3n - 9)
- multiply by the reciprocal of n³ / (3n - 9)
= n³ / (2n - 6) × 1 / n³ / (3n - 9)
= 2n - 6 / 3n - 9
= 2(n - 3) / 3(n - 3)
= 2/3
Therefore, quotient of the fraction n³ / (2n - 6) ÷ n³ / (3n - 9) is 2/3
Learn more about fraction:
brainly.com/question/1622425
#SPJ5
