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Oksana_A [137]
3 years ago
5

Write two multiplication equations using fractions and mixed numbers. Write one equation that will have a product greater than t

he first factor. Then write another equation that will have a product less than the first factor.
Mathematics
1 answer:
HACTEHA [7]3 years ago
7 0
13=6×2 40×5=200>2 that is how solved it.
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Suppose T: ℝ3→ℝ2 is a linear transformation. Let U and V be the vectors given below, and suppose that T(U) and T(V) are as given
ira [324]

Answer:

T(3u+2v)=(-10,29)

Step-by-step explanation:

T is a linear transformation, hence it is homogeneous (T(cr)=cT(r) for all real c and r∈ℝ³) and additive (T(r+s)=T(r)+T(s), for all r,s∈ℝ³). Apply these properties with r=3u and s=2v to obtain:

T(3u+2v)=T(3u)+T(2v)=3T(u)+2T(v)=3(-2,5)+2(-2,7)=(-6,15)+(-4,14)=(-10,29)

We don't have an explicit definition of T, so it's more difficult to compute T(3u+2v) directly without using these properties.

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