Answer:
The distance between A(-8, 4) and B(4, -1) is 13 units.
Step-by-step explanation:
To find the distance between any two points, we can use the distance formula given by:
We have the two points A(-8, 4) and B(4, -1). Let A(-8, 4) be (<em>x₁, y₁</em>) and let B(4, -1) be (<em>x₂, y₂</em>). Substitute:
Evaluate:
So:
The distance between A(-8, 4) and B(4, -1) is 13 units.
Angle TRQ is 23 degrees and the length from S to R is 3.3 units.
I need help on this too
Answer:
The correct answer is option C, 228 feet
Step-by-step explanation:
As per Newton’s third law of motion:
V2 – U2 = 2 x a x S
Where V = final velocity
U = Initial Vlocity
a = acceleration (-ve)
S= distance travelled
V= 0 mph
U= 55 mph = 80.6667 ft /sec
0 – (80.6667 ft /sec)2 = 2 x (-g/2) x S
S = (80.6667 ft /sec)2 /(32.2 feet per second per second x0.5)
S = 202.1 feet
So the most nearest option is option C
Answer:
Number of calls expected in next week by manager = 7940
Average Number of calls that call center agent will attend in an hour =7 calls
It is also given that, Call center remain open for 10 hours 5 days a week.
Also, it is given that, full time agents work 40 hours a week but are only on call for 35 hours per week ,Part time agents work 20 hours a week but are only on calls 17 hours per week .
⇒Number of hours worked by full time agents × Number of calls attended in an hour × Number of full time agents + Number of hours worked by Part time agents × Number of calls attended in an hour × Number of Part time agents ≤ 7940
⇒35 × 7×Number of full time agents +17 × 7 ×Number of Part time agents ≤ 7940
Option A
⇒35×15×7+17×7×15
= 3675+1785
= 5460
Option B
⇒35 ×7×20+17×7×7
=4900 +833
= 5733
Option C
⇒35×20×7 +17×20×7
=4900+2380
=7280
Option D
⇒25 × 35×7+17×7×5
=6125 +595
=6720
Option E
⇒28×35×7+17×7×10
=6860+1190
=8050
Option E, ⇒ 28 full time agents and 10 part time agents , is best to meet the scheduling needs is most appropriate, that is nearer to 7940 calls.
I believe C. Because it provides a more meaningful explanation
