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Leno4ka [110]
2 years ago
10

8 is the difference of d and 3.75

Mathematics
1 answer:
maria [59]2 years ago
7 0

Answer:

11.75

Step-by-step explanation:

From the question above 8 is the difference of d and 3.75

We are required to find the value of d

d-3.75= 8

d= 8 + 3.75

d= 11.75

Hence the value of d is 11.75

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Find the taylor polynomial t3(x) for the function f centered at the number
Vlad [161]
e^{-3x}=\displaystyle\sum_{n=0}^\infty\frac{(-3x)^n}{n!}=1-3x+9x^2+\cdots
\sin2x=\displaystyle\sum_{n=0}^\infty\frac{(-1)^n(2x)^{2n+1}}{(2n+1)!}=2x-\dfrac{4x^3}3+\cdots

e^{-3x}\sin2x=\left(1-3x+9x^2+\cdots\right)\left(2x-\dfrac{4x^3}3+\cdots\right)
\approx T_3(x)=(1-3x+9x^2)\left(2x-\dfrac{4x^3}3\right)
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T_3(x)=2x-6x^2+\dfrac{50}3x^3
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2 years ago
Write a function to represent the point (x,y) being translated of 3 units to the right and 2 units down.
Likurg_2 [28]
The correct answer is C as in cat
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The amount that Jimmy paid for his meals the four days, $6.45, $21.38, $1.99, $7.99, $16, $0, $7.99, $18.95, $4.30, $10.35, $18.
ella [17]

Answer:

$7.99

Step-by-step explanation:

Arrange numbers in numerical order: $0, $1.99, $4.30, $6.45, $7.99, $7.99, $10.35, $16, $18.20, $18.95, $21.38.

Count how many numbers you have, 11.

11 is an odd number so, the number in the middle of the data set is the median.

Final answer: $7.99 is the median.

7 0
2 years ago
The vertex of this parabola is at (2,-1) when the y value is 0 and then x value is 5 what is the coefficient of the squared term
Darina [25.2K]

\bf ~~~~~~\textit{parabola vertex form} \\\\ \begin{array}{llll} \stackrel{\textit{we'll use this one}}{y=a(x- h)^2+ k}\\\\ x=a(y- k)^2+ h \end{array} \qquad\qquad vertex~~(\stackrel{2}{ h},\stackrel{-1}{ k}) \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \begin{cases} h=2\\ k=-1 \end{cases}\implies y=a(x-2)^2-1 \\\\\\ \textit{we also know that } \begin{cases} y=0\\ x=5 \end{cases}\implies 0=a(5-2)^2-1\implies 1=9a \\\\\\ \cfrac{1}{9}=a\qquad therefore\qquad \boxed{y=\cfrac{1}{9}(x-2)^2-1}


now, let's expand the squared term to get the standard form of the quadratic.


\bf y=\cfrac{1}{9}(x-2)^2-1\implies y=\cfrac{1}{9}(x^2-4x+4)-1 \\\\\\ y=\cfrac{1}{9}x^2-\cfrac{4}{9}x+\cfrac{4}{9}-1\implies \stackrel{its~coefficient}{y=\stackrel{\downarrow }{\cfrac{1}{9}}x^2-\cfrac{4}{9}x-\cfrac{5}{9}}

4 0
3 years ago
Read 2 more answers
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