Answer:
➢ 1. Draw base AB of 6cm then construct 90° on A then take a compass and open it 4cm then from point A cut the arc on that 90° and name that point C. Join B to C triangle ABC will be the required triangle.

Answer:
12,5.196
Step-by-step explanation:
given that the radius of a circle is 6.
We have any tangent drawn from outside point there will be two tangents of equal length and also the line joining point of intersection of tangent with centre of circle will bisect the angle between the tangents.
When angle between the two tangents is 60, we have the right triangle formed by radius, one tangent, and line joining point of intersection of tangent with centre of circle with angles 30,60 and 90
Hence the hypotenuse = length of line segment of tangent = 2 (radius) = 12
Part 2:
When angle between tangents is 120, we have 60,30,90 right triangle and hence length of tangent = radius * sin 60
= 
Answer:
This is a problem with translations in the x-axis.
if we have a real positive number a, then for a function f(x), the graph of the function f(x - a) will be the graph of f(x) but translated by a units to the right.
then, if we have f(x - 2) we translate the graph 2 units to the right, if we have f(x + 4) we translate the graph by 4 units to the left.
Then the order, from left to right, is:
f(x + 3)
f(x +2)
f(x)
f(x - 1/2)
f(x - 4)
f(x - 7)
y= mx+b slope intercept form
y = 3.5x +4