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inn [45]
3 years ago
11

I need help with this​

Mathematics
1 answer:
LuckyWell [14K]3 years ago
5 0

Answer:

hhhhhmmmmmmm math yan

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Help answer please!!
12345 [234]

Answer:

h = 19.7 ft.

Step-by-step explanation:

Use the Pythagoras Theorem

(Hypotenuse)^2 = (Base)^2 + (Perpendicular)^2\\\\(20)^2=(3.5)^2+(h)^2\\400=12.25+h^2\\400-12.25=h^2\\387.75=h^2\\

Now we take square root on both sides,

\sqrt{387.75} =\sqrt{h^2}\\19.69=h\\h=19.7\ ft\\

so the value of h equals 19.7 ft.

6 0
3 years ago
Lynn can type 1,650 words in 30 minutes. <br> What is her typing rate, in words per minute?
Marianna [84]
55 words per minute

1650/30 = 55
7 0
3 years ago
Read 2 more answers
How to find x and the equation for it
vladimir2022 [97]

Answer:

Step-by-step explanation:To find the x intercept using the equation of the line, plug in 0 for the y variable and solve for x. You can also use the graph of the line to find the x intercept. Just look on the graph for the point where the line crosses the x-axis, which is the horizontal axis. That point is the x intercept.

8 0
3 years ago
Tabitha received $2,200 from her aunt as a birthday gift. She decided to put the money in an account to save for college. The ac
arsen [322]

3225.36

Step-by-step explanation:

8 0
3 years ago
A basketball player has made 6060​% of his foul shots during the season. Assume the shots are independent. ​
motikmotik

Answer:

a) 2.5 shots

b) 59.4 shots

c) 4.87 shots

Step-by-step explanation:

Probability of making the shot = 0.6

Probability of missing the shot = 0.4

a) The expected number of shots until the player misses is given by:

E(X) = \frac{1}{P(X)}=\frac{1}{0.4}  \\E(X) = 2.5\ shots

The expected number of shots until the first miss is 2.5

b) The expected number of shots made in 99 attempts is:

E=99*0.6\\E=59.4\ shots

He is expected to make 59.4 shots

c) Let "p" be the proportion shots that the player make, the standard deviation for n = 99 shots is:

s=\sqrt{n*p*(1-p)}\\ s= 4.87\ shots

The standard deviation is 4.87 shots.

7 0
3 years ago
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