Answer:
x = 3 and y = 2
or
(3,2)
Step-by-step explanation:
first equation (LCM = 3 x 4 x 5 = 60)
(x+2)/5 - (9-x)/3 = (y - 6)/4
12(x+2) - 20(9-x) = 15(y - 6)
12x + 24 - 180 + 20x = 15y - 90
32x - 15y = -90 - 24 + 180
32x - 15y = 66
second equation:
8(x + 2) - (2x + y) = 2(x + 13)
8x + 16 - 2x - y = 2x + 26
6x - y + 16 = 2x + 26
4x - y = 10
Now you have 2 equations:
4x - y = 10 ---> y = 4x - 10
32x - 15y = 66
Substitute y = 4x - 10 into 32x - 15y = 66
32x - 15(4x - 10) = 66
32x - 60x + 150 = 66
-28x = -84
x = 3
y = 4(3) - 10
y = 12 - 10
y = 2
Solutions: x = 3 and y = 2
Answer:
A) Quantity x minus 5 over quantity x plus 1, where x≠-1 and x≠-9
Step-by-step explanation:

Simplifying the numerator first:
x² + 4x - 45 using the quadratic formula you get;
(x - 5)(x + 9)
Then simplifying the denominator x² + 10x + 9 using a quadratic formula you get;
(x + 1)(x + 9)
Dividing the numerator and denominator now gives;

Cancelling (x + 9) throughout leaves you with;

The only restrictions here is if x = 1 and 9 which will give an undefined answer.