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Tju [1.3M]
2 years ago
5

X–2 1/2=6 3/4. X=? x – 3.23 = 0.77. X=?

Mathematics
2 answers:
Over [174]2 years ago
5 0

Answer:

x= 105/4

x=4

Step-by-step explanation:

BlackZzzverrR [31]2 years ago
4 0

x-2\frac{1}{2} =6\frac{3}{4}      

   +2\frac{1}{2}   +2\frac{1}{2}       add 2\frac{1}{2} on both sides.

__________     solve for 6\frac{3}{4}+2\frac{1}{2}.

x=9\frac{1}{4}, final answer.

x - 3.23 = 0.77

   +3.32   +3.32     add 3.23 on both sides.

____________    solve for 0.77 + 3.23.

x=4, final answer.

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8 0
3 years ago
Find the equation of a line that is perpendicular to y = 3x – 5 and passes through the point (1, -3).
Svetradugi [14.3K]

keeping in mind that perpendicular lines have negative reciprocal slopes, let's check for the slope of the equation above

\begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}\qquad \qquad y = \stackrel{\stackrel{m}{\downarrow }}{3}x-5

well then therefore

\stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}} {\stackrel{slope}{3\implies \cfrac{3}{1}} ~\hfill \stackrel{reciprocal}{\cfrac{1}{3}} ~\hfill \stackrel{negative~reciprocal}{-\cfrac{1}{3}}}

so we're really looking for the equation of a line with slope of -1/3 and that passes through (1, -3 )

(\stackrel{x_1}{1}~,~\stackrel{y_1}{-3})\qquad \qquad \stackrel{slope}{m}\implies -\cfrac{1}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-3)}=\stackrel{m}{-\cfrac{1}{3}}(x-\stackrel{x_1}{1})\implies y+3=-\cfrac{1}{3}x+\cfrac{1}{3} \\\\\\ y=-\cfrac{1}{3}x+\cfrac{1}{3}-3\implies y=-\cfrac{1}{3}x-\cfrac{8}{3}

6 0
2 years ago
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