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2 years ago

8

The cost of buying salad from a salad bar is at least $4.50 per pound. Which inequality represents the price per pound of salad?

1 answer:

Oduvanchick [21]2 years ago

6 0

The cost of buying salad per pound) is more than or equal to $4.50
Step-by-step explanation:
We know from the problem that the salad is going to cost at least $4.50 per pound. Therefore, it is entirely possible for the cost to exceed $4.50, but it cannot be lower than $4.50 because then it would not be equal to $4.50.
So, there would be a greater-than sign pointing toward the s (which I seemingly cannot depict on here for some reason...)

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Find the integration of (1-cos2x)/(1+cos2x)

slega [8]

Given:

The expression is:

$\dfrac{1-\cos 2x}{1+\cos 2x}$

To find:

The integration of the given expression.

Solution:

We need to find the integration of $\dfrac{1-\cos 2x}{1+\cos 2x}$ .

Let us consider,

$I=\int \dfrac{1-\cos 2x}{1+\cos 2x}dx$

$I=\int \dfrac{2\sin^2x}{2\cos^2x}dx$ $[\because 1+\cos 2x=2\cos^2x,1-\cos 2x=2\sin^2x]$

$I=\int \dfrac{\sin^2x}{\cos^2x}dx$

$I=\int \tan^2xdx$ $\left[\because \tan \theta =\dfrac{\sin \theta}{\cos \theta}\right]$

It can be written as:

$I=\int (\sec^2x-1)dx$ $[\because 1+\tan^2 \theta =\sec^2 \theta]$

$I=\int \sec^2xdx-\int 1dx$

$I=\tan x-x+C$

Therefore, the integration of $\dfrac{1-\cos 2x}{1+\cos 2x}$ is $I=\tan x-x+C$ .

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2 years ago

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mariarad [96]

Answer:

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Step-by-step explanation:

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3 years ago

Determine the slope of the line that passes through the points (5, 2) and (-10, -8).

dsp73

Slope = y2-y1 / x2 - x1

= -8-2 / -10-5
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A

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2 years ago

Help me please and thank you

goldenfox [79]

I believe the answer is 78.54 , D

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2 years ago

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Two-step equations with decimals and fractions<br><br> Solve for p.<br><br> −5(p+ 3/5 )=−4

GrogVix [38]

Answer:

1/5 or 0.2

Step-by-step explanation:

-5(p+3/5)=-4

Let's convert 3/5 to decimal form:

-5(p+0.6)=-4

Expand parentheses:

-5p-3=-4

Add -3 to both sides:

-5p=-1

Divide both sides by -5:

p=1/5 or 0.2

Hope this helps!

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2 years ago

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