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dusya [7]
4 years ago
6

Mathew rolls a number cube labeled with the numbers 1−6. He then flips a fair coin. What is the probability that he rolls a 4 an

d flips a head?
Mathematics
2 answers:
KATRIN_1 [288]4 years ago
7 0

Answer:

0.083

Step-by-step explanation:

Numbers of Cube = 6

Faces on coins = 2

Therefore, The total outcomes = 6 \times 2 = 12

Now the favourable outcome that he rolls a 4 & flips a head = 1

The probability that he rolls a 4 & flips a head = 1

\frac{Favourable \: Outcome}{Total \: Outcome}

=> The probability that he rolls a 4 & flips a head = \frac{1}{2}  = 0.83333/ approx. 0.83

Therefore, The probability that he rolls a 4 & flips a head = 0.083

xxMikexx [17]4 years ago
6 0

Answer:

its 1/12

Step-by-step explanation:

just saw the question on edgen

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Answer:

P = 0.3

Step-by-step explanation:

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6 0
4 years ago
Can I have help with the question
sleet_krkn [62]

Answer:

Midpoint = (3.5, 4.5)

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Step-by-step explanation:

[] We can solve this using the midpoint formula:

-> See attached

[] Plug-in our coordinates and solve:

(\frac{7+0}{2} ,\frac{0+9}{2} )=(\frac{7}{2} ,\frac{9}{2} )=(3.5,4.5 )

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-> We will use slope-intercept form, see attached

\frac{9-0}{0-7}=\frac{9}{-7}

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y - 4.5 = \frac{7}{9} x-\frac{49}{18}

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y =  \frac{7}{9} x + \frac{16}{9}

Have a nice day!

     I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)

- Heather

6 0
2 years ago
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Vsevolod [243]

Answer:

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Step-by-step explanation:

Point Form:

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4 0
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(please check interpretation of question b)

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