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Rudiy27
3 years ago
10

Please helppppp :)))

Mathematics
1 answer:
11Alexandr11 [23.1K]3 years ago
4 0

Answer:

jrbfbfbfbxbcvdvdgv

Step-by-step explanation:

bvdbdhdhwofftreytugete

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It would be a 218.182% increase
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*<br> 20% of x is 130. What is x?
densk [106]

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x = 650

Step-by-step explanation:

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Tobin is solving the equation 3 (x minus 1.25) = 11.25. His work is shown below.
Bezzdna [24]

Answer:

tobin should have divided by three

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Please help me figure this out.
xz_007 [3.2K]

Answer:

Quotient: x+7

Remainder: -2

Step-by-step explanation:

Divide the terms (x² ÷ x =x)↓

(x² + 11x + 26) ÷ (x + 4) =x

Subtract x² + 4x (You have to the sign if each term)

(x² + 11x + 26) ÷ (x + 4) =x

-x² - 4x

-------------------

      7x + 26      

Divide the terms (7x ÷ x = 7)

x² + 11x + 26) ÷ (x + 4) =x + 7

Multiply the quotient by the dividend (x + 4) × 7 = 7x+28

(x² + 11x + 26) ÷ (x + 4) =x

-x² - 4x

-------------------

      7x + 26      

      7x + 28

------------------

           = -2 Remainder

4 0
3 years ago
The caffeine content (in mg) was examined for a random sample of 50 cups of black coffee dispensed by a new machine. The mean an
Genrish500 [490]

Answer:

 We are 98% confident interval for the mean caffeine content for cups dispensed by the machine between 107.66 and 112.34 mg .

Step-by-step explanation:

Given -

The sample size is large then we can use central limit theorem

n = 50 ,  

Standard deviation(\sigma) = 7.1

Mean \overline{(y)} = 110

\alpha = 1 - confidence interval = 1 - .98 = .02

z_{\frac{\alpha}{2}} = 2.33

98% confidence interval for the mean caffeine content for cups dispensed by the machine = \overline{(y)}\pm z_{\frac{\alpha}{2}}\frac{\sigma}\sqrt{n}

                     = 110\pm z_{.01}\frac{7.1}\sqrt{50}

                      = 110\pm 2.33\frac{7.1}\sqrt{50}

       First we take  + sign

   110 +  2.33\frac{7.1}\sqrt{50} = 112.34

now  we take  - sign

110 -  2.33\frac{7.1}\sqrt{50} = 107.66

 We are 98% confident interval for the mean caffeine content for cups dispensed by the machine between 107.66 and 112.34 .

               

5 0
3 years ago
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