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3 years ago

35% of the original price of a phone is £78 what was the original price ?

Mathematics

2 answers:

Yakvenalex [24]3 years ago

4 0

Answer:

222.86

Step-by-step explanation:

<h2>in order to solve this question you can create an equation :</h2>

35% * x = 78

where x is the original amount

in order to get x , you have to say :

78/ 35% = x

hence x = 222.8571...

to 2dp = 222.86

Ivanshal [37]3 years ago

4 0

Answer:

£222.86

Step-by-step explanation:

Let the original price be b

That’s 35% of b = £78

Of means multiplication

35%/100% x b = £78

0.35 x b = 78

Divide both sides by 0.35

0.35 x b /0.35 = 78 /0.35

b = 222.857

=£222.86

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An HR director numbered employees 1 through 50 for an extra vacation day contest. What is the probability that the HR director w

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Answer:

The probability that the HR director will select an employee who is not a multiple of 13 is $\frac{47}{50}$

Step-by-step explanation:

* Lets explain how to solve the problem

- The probability of an event is the measure of the chance that the

event will occur

- The probability of an event A is the number of ways that event A can

occur divided by the total number of possible outcomes

- If P(A) is the probability of event A, is the probability that the event A

does not occur is 1 - P(A)

* Lets solve the problem

- An HR director numbered employees 1 through 50 for an extra

vacation day contest

∴ There are 50 employees

- The HR director will select an employee

- We need to find the probability of select an employees who is not

multiple of 13

* At first lets find the multiples of 13

∵ 13 × 1 = 13

∵ 13 × 2 = 26

∵ 13 × 3 = 39

∴ The multiples of 13 from 1 to 50 are 13 , 26 , 39

∵ There are 3 multiples of 13

∵ There are 50 numbers

∵ Probability of multiple of 13 = $\frac{3}{50}$

∵ Probability of not multiple of 13 = 1 - P(multiple of 13)

∴ Probability of not multiple of 13 = $1-\frac{3}{50}$

∴ Probability of not multiple of 13 = $\frac{47}{50}$

* The probability that the HR director will select an employee who is

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