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2 years ago

35% of the original price of a phone is £78 what was the original price ?

Mathematics

2 answers:

Yakvenalex [24]2 years ago

4 0

Answer:

222.86

Step-by-step explanation:

<h2><u>in order to solve this question you can create an equation :</u></h2>

35% * x = 78

where x is the original amount

in order to get x , you have to say :

78/ 35% = x

hence x = 222.8571...

to 2dp = 222.86

Ivanshal [37]2 years ago

4 0

Answer:

£222.86

Step-by-step explanation:

Let the original price be b

That’s 35% of b = £78

Of means multiplication

35%/100% x b = £78

0.35 x b = 78

Divide both sides by 0.35

0.35 x b /0.35 = 78 /0.35

b = 222.857

=£222.86

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It's 4/3 because of the distance formula

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Drew invests $70.00. It earns 50% interest annually.

VladimirAG [237]

Step-by-step explanation:

50% interest annually.

that means he gets 50% interest of the invested capital every year.

and that means he gets 50% of $70 in one year.

70 = 100%

1% = 100%/100 = 70/100 = $0.70

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3 0

11 months ago

2. Given a quadrilateral with vertices (−1, 3), (1, 5), (5, 1), and (3,−1):

zlopas [31]

<h2>Explanation:</h2>

In every rectangle, the two diagonals have the same length. If a quadrilateral's diagonals have the same length, that doesn't mean it has to be a rectangle, but if a parallelogram's diagonals have the same length, then it's definitely a rectangle.

So first of all, let's prove this is a parallelogram. The basic definition of a parallelogram is that it is a quadrilateral where both pairs of opposite sides are parallel.

So let's name the vertices as:

$A(-1,3) \\ \\ B(1,5) \\ \\ C(5,1) \\ \\ D(3,-1)$

First pair of opposite sides:

<u>Slope:</u>

$\text{For AB}: \\ \\ m=\frac{5-3}{1-(-1)}=1 \\ \\ \\ \text{For CD}: \\ \\ m=\frac{1-(-1)}{5-3}=1 \\ \\ \\ \text{So AB and CD are parallel}$

Second pair of opposite sides:

<u>Slope:</u>

$\text{For BC}: \\ \\ m=\frac{1-5}{5-1}=-1 \\ \\ \\ \text{For AD}: \\ \\ m=\frac{-1-3}{3-(-1)}=-1 \\ \\ \\ \text{So BC and AD are parallel}$

So in fact this is a parallelogram. The other thing we need to prove is that the diagonals measure the same. Using distance formula:

$d=\sqrt{(y_{2}-y_{1})^2+(x_{2}-x_{1})^2} \\ \\ \\ Diagonal \ BD: \\ \\ d=\sqrt{(5-(-1))^2+(1-3)^2}=2\sqrt{10} \\ \\ \\ Diagonal \ AC: \\ \\ d=\sqrt{(3-1)^2+(-5-1)^2}=2\sqrt{10} \\ \\ \\$

So the diagonals measure the same, therefore this is a rectangle.

5 0

3 years ago

A figure can be covered by 28 unit squares,without any gaps or overlaps.what is the area of the figure?

Tom [10]

Remember that the area of a square is just one of its sides squared. $A=s^2$
where
$A$ is the area of the square
$s$ is one of the sides of the square

Unit square is a square whose sides have length 1, so lets use our formula to find the volume of one unit square:
$A=s^2$
$A=1^2$
$A=1$
We now know that each one of the squares has area 1 unit squared. Since there are 28 unit square in our figure, we are going to multiply the area of a unit square by 28 to find the area of our figure:
Area of the figure= $28(1)=28$ units squared

We can conclude that the area of the figure is 28 units squared.

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2 years ago