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3 years ago

The relationship between the amount of money a nutritionist earns, m, and the number of

Mathematics

1 answer:

vagabundo [1.1K]3 years ago

7 0

Answer:

The constant of proportionality is 45, and it means the nutritionist earns $45 per hour.

Step-by-step explanation:

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Will choose brainliest! Please help! (This is Khan Academy)

NeTakaya

Answer:

Option B. A = (5/6)^-⅛

Step-by-step explanation:

From the question given above, we obtained:

(5/6)ˣ = A¯⁸ˣ

We can obtain the value of A as follow:

(5/6)ˣ = A¯⁸ˣ

Cancel x from both side

5/6 = A¯⁸

Recall:

M¯ⁿ = 1/Mⁿ

A¯⁸ = 1/A⁸

Thus,

5/6 = 1/A⁸

Cross multiply

5 × A⁸ = 6

Divide both side by 5

A⁸ = 6/5

Take the 8th root of both sides

A = ⁸√(6/5)

Recall

ⁿ√M = M^1/n

Thus,

⁸√(6/5) = (6/5)^⅛

Therefore,

A = (6/5)^⅛

Recall:

(A/B)ⁿ = (B/A)¯ⁿ

(6/5)^⅛ = (5/6)^-⅛

Therefore,

A = (5/6)^-⅛

8 0

3 years ago

Kyra has a rock collection. When she puts her rocks into 2 equal plies, there are no rocks left over. When she puts her rocks in

Nat2105 [25]

Step-by-step explanation:

According to this description we need a number that can be divided by 2,3 and 4 since the amount of rocks can be described by a natural number. However if a number is divided by 4 it is divided by 2 as well since 2*2=4.

$\frac{x}{4} = \alpha \\ \frac{x}{2} = 2 \alpha$

If α is a natural number then 2*α is a natural number as well as the product of two natural numbers.

Which means that we need a number devided by 3 and 4.

The smallest number that fulfills this demand is 3*4=12.

Also any product of 12 with any natural number can be devided by 3, 4 and 2.

If the exercise asks for the numbers that are divided only by 2,3 and 4 these are:

${3}^{ \alpha } \times 12 \: and \: {4}^{ \alpha } \times 12 \: \\ where \: \alpha \: belongs \: to \: the \: set \: of \: all \: \\ natural \: numbers$

8 0

3 years ago

Students receive a 15% discount at the local movie theater. If a student pays the discounted price of $7.65, what is the origina

Over [174]

Answer:

$\large \boxed{\$9.00}$

Step-by-step explanation:

Let p = the original price of the ticket

$\begin{array}{rcl}\text{ Price before discount - discount} & = & \text{sale price}\\p - 0.15p & = & 7.65\\0.85p & = & 7.65\\p & = & \dfrac{7.65 }{0.85}\\\\& = & \mathbf{9.00}\\\end{array}\\\text{The original price of the ticket was $\large \boxed{\mathbf{\$9.00}}$}$