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cricket20 [7]
3 years ago
6

Solve the equations to find the number and type of solutions. The equation 8 − 4x = 0 has real solution(s).

Mathematics
2 answers:
Harman [31]3 years ago
6 0

Answer: only has 1 real solution

Step-by-step explanation:

frez [133]3 years ago
5 0

Answer:

The number of solution is, 1 and the type of solution is, Integer solution.

Step-by-step explanation:

Given the equation:

8-4x=0

Add 4x to both sides we have;

8 = 4x

Divide both sides by 4 we have;

2 = x

or

x = 2

Solution for this equation is, 2

Therefore, The number of solution is, 1 and the type of solution is, Integer solution.

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Find the ratio created when AB is partitioned by C.
Blizzard [7]

Answer:

Step-by-step explanation:

From the picture attached,

Segment AB has been divided into four equal parts.

Let each part measures equal length = 1 unit

Point C is 2 units apart from both the points A and B.

Length of AC = Length of BC = 2 units

Therefore, point C will be the mid point of segment AB.

And ratio of AC and BC = 1:1

AC:BC = 1:1

Similarly, AC:AB = 2:4

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And BC:AB = 2:4

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8 0
3 years ago
What is the prime factorization of 35? 1 • 35 12 • 5 • 7 1 • 5 • 7 5 • 7
Nonamiya [84]

Answer:

  5·7

Step-by-step explanation:

From your knowledge of multiplication tables, you know that ...

  5×7 = 35

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4 0
3 years ago
here are several types of objects. For each type of object, estimate how many there are in a stack that is 5 feet high. Be prepa
lorasvet [3.4K]

We need to estimate how tall is, on average, one of these object, and then count how many would be in a 5 feet high stack.

For example, on Google you may see that "1.5 cubic foot boxes are the standard box, manufactured by most companies". So, we assume that a standard cardboard box is 1.5 feet tall.

So, if we set the equation

1.5k = 5 \iff k=\dfrac{5}{1.5}=3.\bar{3}

So, there would be between 3 and 4 cardboard boxes in a 5 feet tall stack.

Similarly, we can see that the average book is 9 inches tall. 9 inches are 0.75

feet, so we have

0.75k=5 \iff k=6.\bar{6}

So, there would be between 6 and 7 books in a 5 feet tall stack.

The average brick is 75 millimeters tall, which means 0.25 feet tall. Again, we have

0.25k=5 \iff k=20

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Finally, a coin is about 0.006 feet, which leads to

0.006k=5 \iff k=833.\bar{3}

So, there would be between 833 and 834 coins in a 5 feet tall stack.

5 0
3 years ago
The local farmers market has oranges on sale for 5 for 1.80 <br><br>What is the cost of one orange ?
lara [203]

Answer:.36 cent

1Step-by-step explanation:1.80 divided by 5

5 0
3 years ago
Hi! I don't really get these two questions, I would really really appreciate your help. Please if you don't mind include work in
Firlakuza [10]
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