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e-lub [12.9K]
3 years ago
10

Give the domain and range.

Mathematics
1 answer:
Harman [31]3 years ago
3 0

Answer:

The domain: {0, 2, 4}

The range: {2, 6, 10}

Thus, option (a) is correct.

Step-by-step explanation:

From the given diagram

  • The set X = {0, 2, 4}
  • The set Y = {2, 6, 10}

We know that the domain of a relation is the set of all the x-values of the set X. In other words, the domain of relation includes all the input values.

Thus, the domain: {0, 2, 4}

We know that the range of a relation is the set of all the y-values of the set Y. In other words, the range of relation includes all the output values.

Thus, the range: {2, 6, 10}

Therefore, option (a) is correct.

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Use photo math to help you solve the equation and you’ll get the answer for c
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I need the working to the 2nd one
Aleksandr [31]

Answer:

y= -33/32

Step-by-step explanation:

or, 2y/3-3/3=2y+5/8

or, 2y/3-2y=5/8+3/4

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or, -32y =33

or, -y =33/32

or, y= -33/32

4 0
3 years ago
Find two integers whose sum is 1 and product is -2<br> TWO INTERGES
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Answer:

2 and -1

Step-by-step explanation:

sum = 2 + (-1)

= 1

product = 2 × ( -1)

= -2

5 0
3 years ago
If f(x) = 3x + 2 and g(x) = x^2 + 1, which expression is equivalent to (f . g)(x)?
makvit [3.9K]

Answer:

d

Step-by-step explanation:

for this function you have to replace the function of g(x) where there's x in the function f(x) that's what the expression f.g(x) means and so this is going to be

3(x²+1)+2

I hope this helps

5 0
3 years ago
A piece of wire 40 cm long is to be cut into two pieces. One piece will be bent to form a circle and; the other will be bent to
Brums [2.3K]
<h3>The perimeter of circle  = 17.6 cm</h3><h3>Perimeter of square  = 22.4 cm</h3>

Step-by-step explanation:

The total length of the wire  = 40 cm

Let us assume the circumference of the circle  = k cm

So, the circumference of the square  = ( 40 - k) cm

Now,as circumference of circle = 2πR

⇒2πR = k cm    or, R  = (\frac{k}{2\pi})

Area  of the  circle = πR²  

or, A  = \pi (\frac{k}{2\pi} )^2  

 = \pi \times (\frac{k^2}{(2\pi)^2} )  = \frac{k^2}{4 \pi} \\\implies A =  \frac{k^2}{4 \pi}   ....... (1)

Similarly , perimeter of square  = 4 x Side

⇒ 4 x Side  =  ( 40 - k) cm    ⇒ S = (\frac{40 - k}{4} )

Area  of the  square = (Side)²    = (\frac{40 - k}{4} ) ^2

 Solving, we get:  A = \frac{1600 + k^2 - 80 k}{16}   ....... (1)

So, combining (1) and (2), total area A is

A = (\frac{k^2}{4 \pi} ) + \frac{k^2 + 1600 - 80 k }{16}

or, we get: A  = 0.07962 k²  + 0.0625 k² + 100 - 5 k

A  =  0.1422 k² - 5 k + 100

For axis of symmetry :  k = (\frac{-b}{2a} ) = (-\frac{-5}{2(0.1420})  = 17.6

⇒ k = 17.6 inches

So, the perimeter of circle  = 17.6 cm

Perimeter of square  = (40 - 17.6 )  = 22.4 cm

3 0
3 years ago
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