Answer:
A. `1/2` foot
Step-by-step explanation:
The computation of the width of the box is shown below:
15 ÷ 28 = (5 ÷ 7)(1 1 ÷ 2)(width)
15 ÷ 28 = (5 ÷ 7)(3 ÷ 2)width
15 ÷ 28 = (15 ÷ 14)width
(15 ÷ 28) ÷ (15 ÷ 14) = width
(15 ÷ 28) × (14 ÷ 15) = width
w = 14 ÷ 28
= 1 ÷ 2 ft
I'm assuming its asking what time he finished? I added it up and it seems to be 7:42 pm.
Answer:
27.5 minutes
Step-by-step explanation:
Using,
R/R' = 2ᵃ/ᵇ------------------ Equation 1
From the equation,
R = mass of Element X before radioactive decay, R' = mass of element X after radioactive decay, a = Time taken, b = half life.
Given: R = 870 grams, R' = 154 grams, b = 11 minutes.
Substitute these values into equation 1
870/154 = 2ᵃ/¹¹
(870/154)¹¹ = 2ᵃ
Solve for a
2ᵃ = (5.649)¹¹
2ᵃ = 187061.26
Taking the logarithm of both side,
Log2ᵃ = Log(187061.26)
⇒ a = log(187061.26)/log2
a = 8.272/0.301
a = 27.5 minutes
Each time they assume the sum<span> is </span>rational<span>; however, upon rearranging the terms of their equation, they get a contradiction (that an </span>irrational number<span> is equal to a </span>rational number<span>). Since the assumption that the </span>sum of a rational<span> and </span>irrational number<span> is </span>rational<span>leads to a contradiction, the </span>sum<span> must be </span>irrational<span>.</span>
