In the figure below, segment CD is parallel to segment EF and point H bisects segment DE :
1 answer:
Answer:
See explanation
Step-by-step explanation:
In the figure below, segment CD is parallel to segment EF, DE is a transversal, then angles DIH and HGI are congruent as alternate interior angles when two parallel lines are cut by a transversal.
Consider triangles DIH and EGH. In these triangles,
as alternate interior angles;
as vertical angles;
because point H bisects segment DE (given).
Thus,
by AAS postulate
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Answer:
An equation in the slope-intercept form is:
y = a*x + b
Where a is the slope, and b is the y-intercept.
a)
Here we have a slope of 6 and a y-intercept of -3
Then the equation is:
y = 6*x - 3
Now we want to graph this.
To graph it, we first need to find two points (x, y) that belong to this equation, then we can graph the points, and connect them with a line.
To find the points, we evaluate in two different values of x.
x = 0
y = 6*0 - 3 = -3
Then we have the point (0, -3)
x = 1
y = 6*1 - 3 = 3
Then we have the point (1, 3)
The graph of this line can be seen in the image below (the red one)
b) Similar to before, here the slope is -3/5, then the equation is something like:
y = (-3/5)*x + b
Now we also know that the line passes through the point (-10, 8)
This means that when x = -10, we must have y = 8
Replacing these two in the equation we get:
8 = (-3/5)*-10 + b
8 = 6 + b
8 - 6 = 2 = b
Then this equation is:
y = (-3/5)*X + 2
The graph can be found in the same way as before, the graph of this function can also be seen in the image below (the green one)
Answer:
Step-by-step explanation:
assuming the equation is x^2 + (y - 1)^2 = 3
