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Arturiano [62]
3 years ago
9

How fast are you going if you fly 1500 kilometers in just 2 hours?

Mathematics
2 answers:
murzikaleks [220]3 years ago
6 0

Answer:

speed will be 1500/2 = 750km/h

or 208.33 m/s

Gnoma [55]3 years ago
3 0
You are flying 750 per hour
You might be interested in
Jim got 2 out of 5 questions correct on his test. Which is equivalent to 2/5?
Harman [31]
Hey there, 2 out of 5 is 2/5. There are a lot of fractions that is equivalent to 2/5, so I am only going to give you 3, 2/5=4/10, 6/15, and 8/40, 2*2=4 and 5*2=10.
8 0
3 years ago
What is 40+56 in GCF
KengaRu [80]

The GCF stands for greatest common factor. To represent a sum by its GCF we need to use the distributive property and we need to first find the GCF of the numbers. Let's break each number by its factors:

\begin{gathered} 40=2\cdot2\cdot2\cdot5 \\ 56=2\cdot2\cdot2\cdot7 \end{gathered}

We now multiply the numbers that appear on both.

\text{GCF}=2\cdot2\cdot2=8

We now apply the distributive property:

8\cdot(5+7)

3 0
1 year ago
The mean weight of the domesticated house cat is 9.2 pounds with a standard deviation of 3.4 pounds. If a cat has a z-score of -
ra1l [238]

Answer:

4.78 pounds

Step-by-step explanation:

We solve the above question using z score formula

z = (x-μ)/σ, where

x is the raw score

μ is the population mean = 9.2 pound

σ is the population standard deviation = 3.4 pounds

z = 1.3

We are to find x

Hence,

-1.3 = x - 9.2/3.4

Cross Multiply

-1.3 × 3.4 = x - 9.2

-4.42 = x - 9.2

x = -4.42 + 9.2

x = 4.78 pounds.

Therefore the weight of the cat is 4.78 pounds

5 0
3 years ago
Taye recruits two people to be election campaign volunteers. The next week he ask each of those volunteers to recruit two more c
jeka94

Using a geometric sequence, it is found that:

a) For the first 5 weeks, the numbers are: 2, 4, 8, 16, 32

b) Hence some of the volunteers can stop recruiting new volunteers during the 7th week.

<h3>What is a geometric sequence?</h3>

A geometric sequence is a sequence in which the result of the division of consecutive terms is always the same, called common ratio q.

The nth term of a geometric sequence is given by:

a_n = a_1q^{n-1}

In which a_1 is the first term.

For this problem, on the first week there are 2 people, and since each new people involve two more, the common ratio is of 2, hence the parameters for the geometric sequence are:

a_1 = 2, q = 2

Hence the number of people after n weeks is:

a_n = 2 \times 2^{n - 1}

For the first 5 weeks, the numbers are:

  • a_1 = 2 \times 2^{1 - 1} = 2
  • a_2 = 2 \times 2^{2 - 1} = 4
  • a_3 = 2 \times 2^{3 - 1} = 8
  • a_4 = 2 \times 2^{4 - 1} = 16
  • a_5 = 2 \times 2^{5 - 1} = 32

There will be 150 volunteers when a_n = 150, hence:

2 \times 2^{n - 1} = 150

2^{n-1} = 75

\frac{2^n}{2} = 75

2^n = 150

n = 7...

The above is because 2^7 = 128 and 2^8 = 256, and 128 < 150 < 256.

Hence some of the volunteers can stop recruiting new volunteers during the 7th week.

More can be learned about geometric sequences at brainly.com/question/11847927

#SPJ1

3 0
1 year ago
Please answer this question fast in 2 minutes
Dafna1 [17]

Answer:

Angle 4 as it is across from 1 and is equal in size

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
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