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3 years ago

13

Find the area of the shaded half of a baseball field. 90 ft, 90 ft

1 answer:

spin [16.1K]3 years ago

7 0

Answer:

where is the picture??

Step-by-step explanation:

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PLEASE HELP!!!! Thanks!!! :) Select all that are correct.

iren [92.7K]

AB over DE = BC over EF
AC over DF = BC over EF

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3 years ago

Read 2 more answers

Find the perimeter of a rectangle with a width of (x - 3) and a length of 4x

Firdavs [7]

Step-by-step explanation:

4x

__________

| |

x-3| | x-3

| |

|__________

4x

Add all sides together to get perimeter

2(4x)+2(x-3)=10x-6

7 0

3 years ago

(-1,4) and (0, -1)<br> write a linear equation

aniked [119]

The answer and work is shown by the picture given.

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3 years ago

The center of an ellipse is (-9,3). one focus is (-7,3). The major axis is 24 units long. What is the equation of the ellipse in

CaHeK987 [17]

Answer:

$\frac{(x+9)^2}{144}+\frac{(y-3)^2}{140}=1$

Step-by-step explanation:

The standard equation of the ellipse is

$\frac{(x-\alpha)^2}{a^2}+\frac{(y-\beta)^2}{b^2}=1\;\cdots(i)$

where, $(\alpha, \beta)$ is the center and a,b are semi axes of the ellipse along x-axis and y-axis respectively.

Given that, $(\alpha, \beta)=(-9,3)$ and major axis, $2a=24$ .

So, semi major axis, $a=24/2=12$ .

Now, focus of the ellipse is (-7,3).

Let $e$ be the eccentricity of the ellipse,

So, $e=\frac c a$

where $c$ is the distance between the center and focus of the ellipse.

By using the distance formula,

$c=\sqrt{(-9-(-7))^2+(3-3)^2}=2$

$\Rightarrow e=\frac {2}{12}=\frac{1}{6}\;\cdots(ii)$

Again, the relationship among $a,b$ and $e$ is

$e=\sqrt{1-\frac{b^2}{a^2}$

$\Rightarrow \frac{1}{6}=\sqrt{1-\frac{b^2}{(12)^2}$ [from equation (ii)]

$\Rightarrow \frac{1}{36}=\sqrt{1-\frac{b^2}{144}$ [squaring on both the sides]

$\Rightarrow \frac{b^2}{144}=1-\frac{1}{36}$

$\Rightarrow b^2=\frac{35}{36}\times144=140$

So, the value of square of semi-minir axis, $b^2=140$ .

Hence, from equation (i), the equation of required ellipse is standard form is

$\frac{(x-(-9))^2}{144}+\frac{(y-3)^2}{140}=1$

$\Rightarrow \frac{(x+9)^2}{144}+\frac{(y-3)^2}{140}=1$

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3 years ago

A 2-digit number is written on a paper. What is the probability that it starts with 2?

Hatshy [7]

Answer:

1 out of 9

Step-by-step explanation:

4 0

3 years ago