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vekshin1
3 years ago
7

PLEASE HELP ASAP TRIGONOMETRY

Mathematics
1 answer:
otez555 [7]3 years ago
5 0

Answer:

11). x = 25.8°

12). x = 67.3°

Step-by-step explanation:

11). By using sine rule in the given triangle,

   cos(x) = \frac{\text{Adjacent side}}{\text{Hypotenuse}}

   cos(x) = \frac{27}{30}

   x = \text{cos}^{-1}(\frac{9}{10} )

   x = 25.84

   x ≈ 25.8°

12). By applying tangent rule in the given triangle,

    tan(x) = \frac{\text{Opposite side}}{\text{Adjacent side}}

    tan(x) = \frac{43}{18}

    x = \text{tan}^{-1}(\frac{43}{18} )

    x = 67.29°

    x ≈ 67.3°  

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Answer:

Part 1) The inequality that represent this situation is 5(x+7)^{2} \geq1,050  or  5x^{2}+70x+245 \geq1,050

Part 2) Yes, 8 inches is a reasonable width for his tablet

Step-by-step explanation:

Part 1)

Let

L -----> the length of the screen television

W ----> the width of the screen television

x ---->  the width of Andrew's tablet

we know that

L=5W ------> equation A

W=x+7 ----> equation B

The area of the television is

A=LW -----> equation C

Substitute equation A and equation B in equation C

A=5(x+7)(x+7)

A=5(x+7)^{2}

5(x+7)^{2} \geq1,050

5(x^{2}+14x+49) \geq1,050

5x^{2}+70x+245 \geq1,050 ------> inequality that represent this situation

Part 2) Determine if 8 inches is a reasonable width for his tablet

For x=8 in

Substitute in the inequality

5(8+7)^{2} \geq1,050

5(15)^{2} \geq1,050

1,125 \geq1,050 -----> is true

therefore

Yes, 8 inches is a reasonable width for his tablet

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