Answer:
its going to be 20 years
Step-by-step explanation:
1.036
Answer:
Step-by-step explanation:
If the engine torque y (in foot-pounds) of one model of car is given by y=−3.75x^2+23.2x+38.8
The engine speed is at maximum if dy/dx = 0
dy/dx = -2(3.75)x+23.2
dy/dx = -7.5x + 23.2
since dy/dx = 0
0 = -7.5x + 23.2
7.5x = 23.2
x = 23.2/7.5
x = 3.093
Hence the maximum torque is 3.09 rev/min
Answer:
If the time passed is only 3 months, then it is $2040
Step-by-step explanation:
We can use the quarterly compounded interest equation for this problem: P(1 + r/n)^nt
Step 1: Find out how much 3 months is in a year
<em>In this case, 3/12 which is 1/4</em>
Step 2: Plug in known variables into equation
2000[1 + (0.08)/4)]^[(4)(1/4)]
Step 3: Solve/Plug in calc
You will get $2040
If the time passed in the problem is 1 year, then we can be able to solve how much money he earned per quarter. However, since only 3 months have elapsed, then he has only earned $2040.
Answer:
7(7x -4)
Step-by-step explanation:
49x-28
We can factor a 7 from each term
49x = 7*7x
28 = 7*4
7(7x -4)
