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trapecia [35]
2 years ago
13

a mustard seed has a mass of about 0.002 grams a glas jar contains about 4.3602x10e4 seeds what is a estimate of the mass of the

mustard seeds in the jar
Mathematics
2 answers:
san4es73 [151]2 years ago
7 0

Answer:

It has to 4.3 because u divided it from the sum to get the  an porportional answer so u had to solve it from a measurement on how many seeds does which the mass revolves around

Step-by-step explanation:

Anvisha [2.4K]2 years ago
4 0

Answer: the correct answer is D but make sure u read the answer below right.

Step-by-step explanation: (2 x 10 ^-3) x (4 x 10 ^4)=8 x 10 ^1

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Fifteen percent of the students in seventh grade at Western Middle School have perfect attendance. There are 220
Kaylis [27]

Answer: 33

Step-by-step explanation:

4 0
3 years ago
Sale! 25% OFF of the original price! Laura wants to buy a sleeping bag. The original price is $56. How much will Laura pay if sh
goldfiish [28.3K]

Answer:

$14

Step-by-step explanation:

56 × 0.25 = 14

to check this, you can divide 14 ÷ 56 = 0.25

to turn a percentage into a decimal, just divide it by 100

6 0
3 years ago
What is the solution to 9e-7=7e-11<br> need it now
oee [108]

The answer is e = -2

I hope this helped! If so, please mark brainliest!

Step by step solution :

Step  1  :

Pulling out like terms :

1.1     Pull out like factors :

  2e + 4  =   2 • (e + 2)  

Equation at the end of step  1  :

Step  2  :

Equations which are never true :

2.1      Solve :    2   =  0

This equation has no solution.

A a non-zero constant never equals zero.

Solving a Single Variable Equation :

2.2      Solve  :    e+2 = 0  

Subtract  2  from both sides of the equation :  

                     e = -2

8 0
3 years ago
Read 2 more answers
Find a factorization of x² + 2x³ + 7x² - 6x + 44, given that<br> −2+i√√7 and 1 - i√/3 are roots.
Levart [38]

A factorization of x^4+2x^3+7x^2-6x+44 is (x^2+4x+11)(x^2-2x+4).

<h3>What are the properties of roots of a polynomial?</h3>
  • The maximum number of roots of a polynomial of degree n is n.
  • For a polynomial with real coefficients, the roots can be real or complex.
  • The complex roots of a polynomial with real coefficients always exist in a pair of conjugate numbers i.e., if a+ib is a root, then a-ib is also a root.

If the roots of the polynomial p(x)=ax^4+bx^3+cx^2+dx+e are r_1,r_2,r_3,r_4, then it can be factorized as p(x)=(x-r_1)(x-r_2)(x-r_3)(x-r_4).

Here, we are to find a factorization of p(x)=x^4+2x^3+7x^2-6x+44. Also, given that -2+i\sqrt{7} and 1-i\sqrt{3} are roots of the polynomial.

Since p(x)=x^4+2x^3+7x^2-6x+44 is a polynomial with real coefficients, so each complex root exists in a pair of conjugates.

Hence, -2-i\sqrt{7} and 1+i\sqrt{3} are also roots of the given polynomial.

Thus, all the four roots of the polynomial p(x)=x^4+2x^3+7x^2-6x+44, are: r_1=-2+i\sqrt{7}, r_2=-2-i\sqrt{7}, r_3=1-i\sqrt{3}, r_4=1+i\sqrt{3}.

So, the polynomial p(x)=x^4+2x^3+7x^2-6x+44 can be factorized as follows:

\{x-(-2+i\sqrt{7})\}\{x-(-2-i\sqrt{7})\}\{x-(1-i\sqrt{3})\}\{x-(1+i\sqrt{3})\}\\=(x+2-i\sqrt{7})(x+2+i\sqrt{7})(x-1+i\sqrt{3})(x-1-i\sqrt{3})\\=\{(x+2)^2+7\}\{(x-1)^2+3\}\hspace{1cm} [\because (a+b)(a-b)=a^2-b^2]\\=(x^2+4x+4+7)(x^2-2x+1+3)\\=(x^2+4x+11)(x^2-2x+4)

Therefore, a factorization of x^4+2x^3+7x^2-6x+44 is (x^2+4x+11)(x^2-2x+4).

To know more about factorization, refer: brainly.com/question/25829061

#SPJ9

3 0
1 year ago
Read 2 more answers
A person travelled 9 hours a day what percentage of the day was spent on this journey​
Galina-37 [17]

Answer:

37.5%

Step-by-step explanation:

one day has 24 hours

100%->24

1%->0.24

9÷0.24 = 37.5%

7 0
3 years ago
Read 2 more answers
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