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Artemon [7]
3 years ago
5

Write an explicit formula for an, the nth term of the sequence 11, 20, 29

Mathematics
1 answer:
photoshop1234 [79]3 years ago
7 0
On = 38 - 9n
Step-by-step explanation:
Note the common difference d between
consecutive terms
d= 20 - 29 = 11 - 20 = - 9
This indicates the sequence is arithmetic with n
th term
On
= apt (n - 1)d
where a, is the first term and d the common
difference
Here a, = 29 and d=- 9, thus
An = 29 - 9 (n - 1) = 29 - 9n + 9 = 38 - 9n
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Aleksandra started studying how the number of branches in her tree grows over time. Every 1.5 years, the number of branches incr
vova2212 [387]

Answer:

N = 52 * (9/7)^(t/1.5)

Step-by-step explanation:

This problem can be modelated as an exponencial problem, using the formula:

N = Po * (1+r)^(t/1.5)

Where P is the final value, Po is the inicial value, r is the rate and t is the amount of time.

In our case, we have that N is the final number of branches after t years, Po = 52 branches, r = 2/7 and t is the number of years since the beginning (in the formula we divide by 1.5 because the rate is defined for 1.5 years)

Then, we have that:

N = 52 * (1 + 2/7)^(t/1.5)

N = 52 * (9/7)^(t/1.5)

7 0
3 years ago
Write an equation of the line that passes through (2, -5) and is parallel to the line 2y = 3x + 10.
Leto [7]

Answer:

Use the given slope and point to substitute into the point-slope formula y−y1=m(x−x1).

Slope-intercept form:

y=3x²+4x−25

Point-slope form:

y+5=(3x+10)⋅(x−2)

Step-by-step explanation:

8 0
3 years ago
How do you solve -28-6x=-2(1-3x)-2
Zina [86]

-28-6x=-2(1-3x)-2

-28-6x=-2+6x-2

-28-6x=-4+6x

-6x-6x=-4+28

-12x=24

x=-2

6 0
3 years ago
Read 2 more answers
The graph of y=ax^2+bx+c passes through points (0,5), (1,10), and (2,19). Find a+b+c.
nataly862011 [7]

Answer:   a = 2   b = 3   c = 5  

Literally a+ b+c = 10, but I don't think that's what the question means to ask.

the equation is 2x² +3x + 5

Step-by-step explanation:   Substitute the values of the given coordinates into the formula and use algebra (solve a system of equations by substitution and elimination) to get the values  of a,b & c

y=ax²+bx+c    using  (0,5), (1,10), and (2,19)

5=a(0)²+b(0)+c   becomes 5= 0+0 + c .so we find c = 5

10=a(1)²+b(1)+c    becomes 10 = a + b + c

19=a(2)²+b(2)+c .  becomes 19 = 4a + 2b + c

Substitute the 5 for c.  Then rewrite

10 = a + b + 5      becomes     5 = a+ b     to eliminate b multiply this be (-2)

(-2)( 5 = a+ b) .to get -10 = -2a - 2b  

19 = 4a + 2b + 5  becomes   14 = 4a + 2b  

_______________  Add these two

14 = 4a + 2b

<u>-10 = -2a - 2b</u><u> </u>    this will eliminate the "b" term

4 = 2a       divide both sides by 2   so you have   a = 2  

substitute in 10=a(1)²+b(1)+5 to find b

10=2(1)²+b(1)+5 .becomes  5 = 2 + b   Subtract 2 from both sides

b = 3

So now you have all three values:  

a = 2  b= 3  c = 5  

I am attaching the graph. I hope this deserves Brainiest.

Best wishes in your studies!

4 0
3 years ago
PLEASE HELP ME ASAP!!
solong [7]
We have to find midpoint M of the diagonal AC (or BD, there is no difference) so:

M=\left(\dfrac{x_A+x_C}{2},\dfrac{y_A+y_C}{2}\right)=\left(\dfrac{-2+4}{2},\dfrac{4+(-2)}{2}\right)=\left(\dfrac{2}{2},\dfrac{2}{2}\right)=\\\\\\=\boxed{(1,1)}
5 0
3 years ago
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