Answer:
$353.05
Explanation:
To calculate this, the loan amortization formula is employed as follwow:
P = {A × [r(1 + r)^n]} ÷ {[(1+r)^n]-1} .................................... (1)
Where,
P = Monthly required payment = ?
A = Loan amount = $7,500
r = monthly interest rate = (0.12 ÷ 12) = 0.01
n = number of payment period = 24 months
Substituting all the figures into equation (1), we have:
P = {7,500 × [0.01(1 + 0.01)^24]} ÷ {[(1 + 0.01)^24]-1} = $353.05
Therefore, the amount of monthly payments is $353.05.
On basis of straight-line depreciation method,
Yearly depreciation expense = [Cost of investment - Salvage value] / life
In the current case, salvage vale is assumed to be $0 and the life is 7 years.
Total investment = $4 m + $ (15,000/1,000,000) m + $3 m = $7.015 m
Therefore,
Yearly depreciation expense = 7.015/7 ≈ $1.002 m
Pretty sure it’s B since Marcos is using cash
Answer: So that Revenue, expense, and dividends accounts must begin each period with zero balances
Explanation:
Answer:
Explanation:
Number of completed barrels = 216 + (244-216)*60%
= 233 barrels
Cost per barrel = (3245+3230)/233 = 27.8
Cost of oil shipped in pipeline = 216 * 27.8= 6003 millions
Cost of work in process ending inventory = (244-216)*60% * 27.8
= 467.04 million
