Rate this app 1/10 and explain why
2 answers:
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Answer:
Kindly check explanation
Step-by-step explanation:
Given the data :
Rearranged data:
5, 5, 5, 5, 6, 7, 7, 7, 8, 12, 12, 13, 13, 15, 18, 18, 27, 28, 36, 48, 52, 60, 66, 94
Start time for Suriname = 694
Mean = ΣX / n
Mean = (567 + 694) / (24 + 1) = 1261 / 25 = 50.44
B.) median start Time for initial 24 values
0.5(n+1)th term
0.5(25) = 12.5th term
(13 + 13) / 2 = 13
C.) preferred measure of center for the distribution will be the median as it shapes well in the middle of the distribution. The mean is overestimated
d) Compute the quartiles (Q1, Q2, Q3), and find the IQR for these data. Are there outliers in the time to start a business data set? If so, identify and name any outliers.
Using calculator :
Lower quartile Q1 --> 7
Median Q2 --> 13
Upper quartile Q3 --> 42
IQR = (Q3 - Q1) = 42 - 7 = 35
OUTLIER:
Lower bound : Q1 - 1.5(IQR) ; 7 - 1.5(35) = - 45.5
Upper bound : Q3 + 1.5(IQR) = 42 + 1.5(35) = 94.5
Outlier : values below - 45.5 and above 94.5
Hence, Surimanes start time is the only Outlier.
e)
Standard deviation for 24 countries :
Standard deviation = sqrt[Σ(X - mean)^2 / (N - 1)]
Usibg calculator :
Standard deviation for the 24 countries is 23.83
f)
Standard deviation
Answer:
A) Approximate percentage of women with platelet counts within 2 standard deviations of the mean, or between 118.5 and 377.3 = 95%
B) approximate percentage of women with platelet counts between 53.8 and 442.0 = 99.7%
Step-by-step explanation:
We are given;
mean;μ = 247.9
standard deviation;σ = 64.7
A) We want to find the approximate percentage of women with platelet counts within 2 standard deviations of the mean, or between 118.5 and 377.3.
Now, from the image attached, we can see that from the empirical curve, the probability of 1 standard deviation from the mean is (34% + 34%) = 68 %.
While probability of 2 standard deviations from the mean is (13.5% + 34% + 34% + 13.5%) = 95%
Thus, approximate percentage of women with platelet counts within 2 standard deviations of the mean, or between 118.5 and 377.3 = 95%
B) Now, we want to find the approximate percentage of women with platelet counts between 53.8 and 442.0.
53.8 and 442.0 represents 3 standard deviations from the mean.
Let's confirm that.
Since mean;μ = 247.9
standard deviation;σ = 64.7 ;
μ = 247.9
σ = 64.7
μ + 3σ = 247.9 + 3(64.7) = 442
Also;
μ - 3σ = 247.9 - 3(64.7) = 53.8
Again from the empirical curve attached, we cans that at 3 standard deviations from the mean, we have a percentage probability of;
(2.35% + 13.5% + 34% + 34% + 13.5% + 2.35%) = 99.7%
