Answer:
1/5
Step-by-step explanation:
To find what fraction of the total price the battery is, we need to find out how much the battery alone is first.
Since the battery and torch together are £2.50 and the torch is £2.00, we can find the price of the battery by subtracting the total price to the price of the torch.
Battery Price = £2.50 - £2.00
Battery Price = £0.50
The fraction value of the torch is:
2.00 of 2.50 = 4/5
That then leaves us with:
0.50 of 2.50 = 1/5
To check we need to add the two fractions together.
1/5 + 4/5 = 5/5 or 1
Answer:

Step-by-step explanation:
First of all we need to know the relation between 1 dollar and 1 cent in order to express everything in the units required in the question.
We know that
, so the amount paid for the item with single dollars has to be multiplied by 100 to express its value in cents.

Now that we have everything in cents, we can make the subtraction:

Replacing the value in cents we get:

Answer:
x = -2 y = -8
Step-by-step explanation:
13x - 6y = 22
x - y = 6
6(x-y) = 6*6
6x - 6y = 36
subtract both the equations
13x - 6x -6y + 6y = -14
7x = -14
x = -2
13*-2 -6y=22
-26 -6y=22
-6y = 48
y = -8
answer: x = -2 y = -8
Answer:
1199
Step-by-step explanation:
There are 22 terms in the sum:
23 + 26 + 29 + ... + 80 + 83 + 86 =
= (23 + 86) + (26 + 83) + ... + (53 + 56)
= 109 + 109 + ... + 109
= 11(109)
= 1199
Answer:
a rectangle is twice as long as it is wide . if both its dimensions are increased 4 m , its area is increaed by 88 m squared make a sketch and find its original dimensions of the original rectangle
Step-by-step explanation:
Let l = the original length of the original rectangle
Let w = the original width of the original rectangle
From the description of the problem, we can construct the following two equations
l=2*w (Equation #1)
(l+4)*(w+4)=l*w+88 (Equation #2)
Substitute equation #1 into equation #2
(2w+4)*(w+4)=(2w*w)+88
2w^2+4w+8w+16=2w^2+88
collect like terms on the same side of the equation
2w^2+2w^2 +12w+16-88=0
4w^2+12w-72=0
Since 4 is afactor of each term, divide both sides of the equation by 4
w^2+3w-18=0
The quadratic equation can be factored into (w+6)*(w-3)=0
Therefore w=-6 or w=3
w=-6 can be rejected because the length of a rectangle can't be negative so
w=3 and from equation #1 l=2*w=2*3=6
I hope that this helps. The difficult part of the problem probably was to construct equation #1 and to factor the equation after performing all of the arithmetic operations.