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bulgar [2K]
3 years ago
11

Find the gradient of the curve y=(2x-3)^5 at the point (2,1)

Mathematics
2 answers:
Setler [38]3 years ago
6 0
<h3><em>Hope I helped you!</em></h3><h3><em>Success!</em></h3>

AfilCa [17]3 years ago
5 0

Answer:

(-10,1)

Step-by-step explanation:

Caculating the gradient:

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Bogdan [553]

Answer:

x = 9 or x = 0

Step-by-step explanation:

Solve for x over the real numbers:

x^2 - 4 x - 5 x = 0

x^2 - 4 x - 5 x = x^2 - 9 x:

x^2 - 9 x = 0

Factor x from the left hand side:

x (x - 9) = 0

Split into two equations:

x - 9 = 0 or x = 0

Add 9 to both sides:

Answer: x = 9 or x = 0

7 0
3 years ago
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Please help me out....
Agata [3.3K]

Answer:

x = 6

Step-by-step explanation:

Given that the line segment is an angle bisector then the following ratios are equal

\frac{42}{78} = \frac{6x-1}{10x+5}, that is

\frac{7}{13} = \frac{6x-1}{10x+5} ( cross- multiply )

13(6x - 1) = 7(10x +5) ← distribute parenthesis on both sides

78x - 13 = 70x + 35 ( subtract 70x from both sides )

8x - 13 = 35 ( add 13 to both sides )

8x = 48 ( divide both sides by 8 )

x = 6

7 0
3 years ago
What is the recursive formula for the geometric sequence with this explicit formula? an=6*(-1/4)^(n-1)
igomit [66]

Answer:

A

Step-by-step explanation:

The explicit formula for a geometric sequence is

a_{n} = a₁(r)^{n-1}

where a₁ is the first term and r the common ratio

Given the explicit formula

a_{n} = 6(-\frac{1}{4}) ^{n-1}

where a₁ = 6 and r = - \frac{1}{4}

A recursive formula allows any term in the sequence to be found by multiplying the previous term by r , thus

a_{n} = a_{n-1} (- \frac{1}{4}) with a₁ = 6 → A

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3 years ago
Wholesome Food Company has been hired to design a healthy menu for the cafeteria at Ridgemont High School. They want to conduct
Alekssandra [29.7K]

Answer:

Step-by-step explanation: 15%

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4 years ago
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I need you to solve this question for me it is about 2020
Serga [27]
We use the formula y=mx+b and we replace the variables with the amount of coffee that I drink in 1 day and the answer is 5 years
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