bearing in mind that an absolute value expression is in effect a piece-wise expression, because it has a ± version.
![\bf 3|x|+7=28\implies 3|x|=21\implies |x|=\cfrac{21}{3}\implies |x|=7\implies \begin{cases} +(x)=7\\ -(x)=7 \end{cases} \\\\[-0.35em] ~\dotfill\\\\ +(x)=7\implies \boxed{x=7}~\hfill -x=7\implies \boxed{x=-7}](https://tex.z-dn.net/?f=%20%5Cbf%203%7Cx%7C%2B7%3D28%5Cimplies%203%7Cx%7C%3D21%5Cimplies%20%7Cx%7C%3D%5Ccfrac%7B21%7D%7B3%7D%5Cimplies%20%7Cx%7C%3D7%5Cimplies%20%20%5Cbegin%7Bcases%7D%20%2B%28x%29%3D7%5C%5C%20-%28x%29%3D7%20%5Cend%7Bcases%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%2B%28x%29%3D7%5Cimplies%20%5Cboxed%7Bx%3D7%7D~%5Chfill%20%20-x%3D7%5Cimplies%20%5Cboxed%7Bx%3D-7%7D%20)
Answer:
Kindly check explanation
Step-by-step explanation:
Given the question :
Grace wove a potholder with an area of 80 square inches. The lengths and widths of the sides are whole numbers. Which dimensions make the most sense for a potholder?
Since the Area of the potholder = 80 sq inch
And the dimension of the potholder ; length and width are integers ; Hence, possible dimensions could be ;
Area = length × width
80 = length × width
(80, 1), (40, 2), (20, 4), (10, 8), (16, 5)
Potholders are fabrics sewn from the purpose of being used to handle pots and other kitchen equipments.
Usually the dimension are usually close, hence, the most sensible dimension a potholder with an area of 80 sq inch could have is 8 by 10 or vice-versa.
Answer:
A
Step-by-step explanation:
-5 i s greater than -2.
Nope that aint true
-2 is greater than -5 is correct since -2 is closer to the postivie numbers and zero.
-5 is farther so it is less than -2.
Answer:
10, 14
Step-by-step explanation:
take the x values and plug into mid point formula and then divide by 2
so... (-214 + 234) divided by 2 = 10
do the same for the y values
so ... (14 + 14) divided by 2 = 14
so ... 10,14
