Let x = # of tickets sold in advance
Let y = # of tickets sold the day of
Cost of the tickets & total sales: 6x & 10y = 6828
You also know y = x + 206
Take the equation mentioned above y = x + 206 and sub it in anywhere the variable y is in the other equations so you'll have this:
6x + 10(x+206) = 6828
Now solve for x to get x = 298
To finish the problem, you must now find the number of y tickets sold.
Sub your x value that you found back into the equation y = x + 206 and you'll get y = 504.
So, 298 tickets were sold in advance and 504 tickets were sold the day of
In here, we will use the distance formula
Compute the distance between <span>(-5, 3) and (5, 3)
</span>
<span>
= 10
The distance between </span>(-5, 3) and (5, 3) is 10
Step-by-step explanation:
David makes 17(25)
and
Linda maked 25(7)
so it would make the equation 17(25)+25(7)
425+175 together they would be making
600 dollars a week
(50,45)(125,37.50)
slope(m) = (37.50 - 45) / (125 - 50) = -7.5/75 = -0.1
y = mx + b
slope(m) = -0.1
(50,45)...x = 50 and y = 45
now we sub and find b, the y int
45 = -0.1(50) + b
45 = - 5 + b
45 + 5 = b
50 = b
so ur equation is : y = -0.1x + 50
so it the staff sells 150 yearbooks...
y = -0.1x + 50
y = -0.1(150) + 50
y = -15 + 50
y = 35 <== price per yearbook
Answer:
It is usually an integer that is multiplied by the variable next to it.
Step-by-step explanation:
