Answer:
YES
Step-by-step explanation:
Find the equation of the line written as, y = kx. The graph shows a proportional relationship between y and x.
Constant of proportionality/unit rate/slope (k) = rise/run = ⁵/4.
Substitute ⁵/4 in y = kx
We would have:
y = ⁵/4x.
Using the equation of the line, we can know if a given point is on the line by plugging the value of x and y coordinates of the point into the equation. If it makes the equation true, then it is a point on the line. If it doesn't make the equation true, then it isn't a point on the line.
Let's plug in (16, 20) into y = ⁵/4x.
Thus substitute x = 16 and y = 20, we have:
[tex] 20 = \frac{5}{4}(16) [/trex]
[tex] 20 = (5)(4) [/trex]
[tex] 20 = 20 [/trex]
It makes the equation true. Therefore, the point, (16, 20) is a point on line l.
18 is D and 19 is C you're welcome
The answer to your first question would be B, because in the word problem it says that she buys 6 pots, so therefore we can eliminate A and C. We are left with B and D. Now looking at the second equation, we see that x represents the 5 inch pots, which are $12. This would mean 12x, because if she bought 1 5 inch pot, she would spend $12, and the same way, 10 inch pots are represented by y, or $15. Pretty much, multiply the number of 10 inch pots she buys by 15. Therefore the answer is B.
Question 3 says that the sum of their ages are 105. So the first equation should be S + R = 105. The second part of the question says that Sara is 33 years younger than Rolando. This means 33 + Sara's age, represented by S, should equal Rolando's age. That is S + 33 = R.
Hope this helps. Please rate, leave a thanks, and mark a brainliest answer (Not necessarily mine). Thanks, it really helps! :D
Answer:
No Solutions
Step-by-step explanation:
Let's find out.
-2(t-4)=10-2t
-2t+8=10-2t
-2t=2-2t
0=2
Hope this helps :)
The negative sign will have an effect in terms of which way the graph opens up. Since the function starts off negatively the graph will open down, like an upside down U. Rather if the function started off positive I.e Y=x^2 the graph will open upwards like a upright U.
