9514 1404 393
Answer:
Step-by-step explanation:
Let x and y represent amounts invested at 6% and 9%, respectively.
y = 3x +58 . . . . . . . the amount invested at 9%
0.06x +0.09y = 1097.19 . . . . . . total interest earned
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Substituting for y, we have ...
0.06x +0.09(3x +58) = 1097.19
0.33x + 5.22 = 1097.19 . . . . . . . . . simplify
0.33x = 1091.97 . . . . . . . . . . . . subtract 5.22
x = 3309 . . . . . . . . . . . . . . . . divide by 0.33
y = 3(3309) +58 = 9985
$3309 is invested at 6%; $9985 is invested at 9%.
Title:
<h2>The revenue will be maximum for 253 passengers.</h2>
Step-by-step explanation:
Let, the number of passenger is x, which is more than 194.
In this case, the travel agency will charge [312 - (x - 194)] per passenger.
The total revenue will be ![x[312 - (x - 194)] = 506x - x^{2}](https://tex.z-dn.net/?f=x%5B312%20-%20%28x%20-%20194%29%5D%20%3D%20506x%20-%20x%5E%7B2%7D)
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As x is the variable here, we can represent the revenue function by R(x). Hence, 
.
The revenue will be maximum when 
.
The answer is the graph will be 3 units to the left
It's the first choice.Correlation that implies causation
Let, the number of toy trucks = x
Then, number of toy cars = (x + 12)
Now, we have: x + x+12 = 38
2x + 12 = 38
2x = 38 - 12
2x = 26
x = 26/2
x = 13
So, there are 13 toy trucks in total.
Hope this helps!
